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Stella [2.4K]
3 years ago
8

I don't know how to do this

Mathematics
1 answer:
Phantasy [73]3 years ago
3 0
I completely agree with the above statement
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Which of the choices below is not a possible correlation coefficient?
fiasKO [112]

Answer:

The condition for r is the following:

-1 \leq r \leq 1

And for this case if we analyze the options the only impossible value is given by:

1.0528

Because this value is higher than 1 and not satisfy the general limits for r

Step-by-step explanation:

The correlation coefficient is a measure of dispersion and is a value between -1 and 1, and is defined as:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}

The condition for r is the following:

-1 \leq r \leq 1

And for this case if we analyze the options the only impossible value is given by:

1.0528

Because this value is higher than 1 and not satisfy the general limits for r

8 0
3 years ago
A ray lies on the line MN←→−. It starts at point Q and passes through the points P and R. Which of the following is a correct na
pogonyaev

Answer:

please mark my answer brainliest

Step-by-step explanation:

the correct name will be QP...or QR

3 0
3 years ago
Please i need help i will mark you brill
Furkat [3]

Answer:

the answer to your question is

2n + 20

4 0
3 years ago
Read 2 more answers
Find the gross pay for 39 hours at $8.17 per hour
skelet666 [1.2K]
It is a simple multiplication problem. If you work for 39 hours, and you get paid $8.17 for every hour you work, just multiply 8.17 by 39 to get the gross pay.

8.17 x 39 = 318.63

The gross pay is $318.6.

Hope this helps =)
8 0
3 years ago
Read 2 more answers
Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean equal to 23.

This means that m = 23, \mu = \frac{1}{23} = 0.0435

(a) P(X >10)

P(X > 10) = e^{-0.0435*10} = 0.6473

So

P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

5 0
3 years ago
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