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AVprozaik [17]
3 years ago
9

Which of the following is the number 0.008005 written in scientific notation?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0
A. 8.005 • 10² = 800.5 (Incorrect)

B. 8.500 • 10⁻³ = 0.0085 (Incorrect)

C. 8.005 • 10⁻⁴ = 0.000801 (Incorrect)

D. 8.005 • 10⁻³ = 0.008005 (Correct)

Answer: D. 8.005 • 10⁻³
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You are arguing over a cell phone while trailing an unmarked police car by 25 m; both your car and the police car are traveling
BARSIC [14]

Answer:

  (a) 15 m

  (b) ground speed: 26.14 m/s (94.1 km/h); relative speed 12 m/s

Step-by-step explanation:

We can choose the frame of reference to be the trailing car. We can start counting time from the point the lead car begins deceleration. Then its position (in meters) relative to the trailing car is ...

  d(t) = 25 - 5/2t² . . . . . . where 25 m is the initial distance and -5 is the acceleration in m/s².

(a) Then the distance between cars at t=2 is ...

  d(2) = 25 - (5/2)·4 = 15 . . . . meters

__

(b) The <em>relative velocity</em> at 2.4 seconds is ...

  d'(t) = -5t

  d'(2.4) = -5(2.4) = -12.0 . . . m/s

The closure speed with the police car is 12 m/s.

__

We need to do a little more work to find the ground speed of the trailing car when the cars bump.

The distance between the cars at t=2.4 seconds is ...

  d(2.4) = 25 -(5/2)2.4² = 10.6 . . . . meters

At the closure speed of 12 m/s, it will take an additional ...

  10.6 m/(12 m/s) = 0.8833... s = 53/60 s

to close the gap. The speed of the trailing car at that point in time will be the original speed less the deceleration for 0.8833 seconds:

  (110 km/h)·(1/3.6 (m/s)/(km/h))-(5 m/s²)(53/60 s)

     = 26 5/36 m/s = 94.1 km/h

_____

<em>Comment on following distance</em>

To avoid collision, the trailing car must be trailing by at least the distance it covers in 2.4 seconds, about 73 1/3 meters.

6 0
3 years ago
Manish and Jhanavi each receive an equal bonus. Manish has 1/2 fraction of allowance as saving accounts , 1/4 of the fraction he
Valentin [98]

Answer:

Manish has Rs630 while Jhanavi has Rs168.

Step-by-step explanation:

The fraction Manish would have left would be subtracting the fraction on savings as well as that spent on the mall. Which would be;

1 -( 1/2 + 1/4)=1 -3/4 = 1/4

Meaning Manish had 1/4 of his allowance left on him.

Which means 1/4 × Rs. 2520=Rs630

Similarly for Jhanavi, we have :

The fraction left as

1-(1/3 +3/5) = 1 - ( 14/15) = 1/15

Meaning 1/15 of the allowance got remains which is;

1/15 × Rs. 2520= Rs.168

3 0
3 years ago
Show me a step by step work and solve the problem
AveGali [126]
What’s the question?
6 0
3 years ago
Triangle ABC has coordinates A (0, 1) B (0, 2) and C (3,2). If Triangle ABC is equivalent to triangle EDF, what is the measure o
Elanso [62]

Answer:

  3

Step-by-step explanation:

Segment BC corresponds to segment DF. The length of BC is the distance between coordinates (0, 2) and (3, 2). These points are on the same horizontal line (y=2), so the distance between them is the difference of their x-coordinates: 3 - 0 = 3.

7 0
3 years ago
Read 2 more answers
Find the exponential function that satisfies the given conditions: Initial value = 70, decreasing at a rate of 0.43% per week
dimulka [17.4K]
That'd be y = 70* (1-.00043)^t, where the rate of decrease is really 0.43% and t denotes the # of weeks.  

This simplifies to y = 70*(0.00057)^t. 
                                 
4 0
3 years ago
Read 2 more answers
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