The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Adding fractions is easy when you get the rules...
10/12 + 6/12...
add the numerator which is the top, and keep the denominator which is the bottom.
10/12 +6/12 = 16/12
change that into a mixed number
16/12 = 1 4/12 which is simplified to 1 1/3
hope this helps
X - the number
3(x+1)=2x+4
3x+3=2x+4
3x-2x=4-3
x=1
You can replace the h and w with 6 and 3 in the expression. Then the expression is 12*6+30*3=162 dollars. So the amount paid to this employee is 162 dollars.
In total would be 00.08 because you need to divide to get your answer
