No.
The 3 angles of a triangle need to equal 180 degrees.
The sum of the 3 given angles is greater than 180 ( 160 + 20 + 20 = 200) so it cannot form a triangle.
Answer:
see explanation
Step-by-step explanation:
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ 4 , ∠ 5 , ∠ 6 are exterior angles of the triangle
-------------------------------------------
(14)
∠ 1 and ∠ 4 are adjacent angles and sum to 180° , then
∠ 1 = 180° - 58° = 122°
∠ 2 + ∠ 3 = ∠ 4
∠ 2 + 32° = 58° ( subtract 32° from both sides )
∠ 2 = 26°
∠ 5 = ∠ 1 + ∠ 3 = 122° + 32° = 154°
∠ 6 = ∠ 1 + ∠ 2 = 122° + 26° = 148°
(15)
∠ 4 = ∠ 2 + ∠ 3 = 11° + 143° = 154°
∠ 1 = 180° - ∠ 4 = 180° - 154° = 26°
∠ 5 = ∠ 1 + ∠ 3 = 26° + 143° = 169°
∠ 6 = ∠ 1 + ∠ 2 = 26° + 11° = 37°
Answer:
240$
Step-by-step explanation:
$200
OCS
$230
$240
$310
ABCDA. $960
ACDBA. $900
ACBDA. $960
=240
Answer:
x = 12
Step-by-step explanation:
The sum of exterior angles is = 360
one of the angle is given we will need to add all three angles
128 + 8x + 11x + 4 = 360 add like terms
19x + 132 = 360 subtract 132 from both sides
19x = 268 divide both sides by 19
x = 12 replace x in required expressions to find the measure of the angles
Answer:
30.5 ; 49 ; 27 ; 50 ; 45
Step-by-step explanation:
Determine the first and third quartiles. Determine the second decile and the eighth decile. Determine the 67th percentile
Given the ordered data :
13 13 13 20 26 27 29 32 34 34 35 35 36 37 38 41 41 41 42 44 46 47 48 50 53 55 56 62 67 82
Sample size, n = 30
The first quartile ;Q1
Q1 = 1/4(n+1)th term
Q1 = 31/4 = 7.75th term
Q1 = (29+32)/2
Q1 = 30.5
Q3 ;
Q3 = 3/4(n+1)th term
Q3 = 3(31)/4 = 23.25 th term
Q3 = (48 + 50) /2 = 49
2nd decile :
0.2 * (nth term
0.2 * 30 = 6th term = 27
8th decile :
0.8 * 30 = 24 th term
= 50
67th percentile :
0.67 * (n+1)th term
0.67 * 31 = 20.77
= (44 + 46) / 2
= 45
