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3 years ago

An isotope of cesium has 55 protons and 78 neutrons. What is the mass number of this isotope?

Chemistry

1 answer:

mixer [17]3 years ago

4 0

The only stable caesium isotope is 133Cs, with 78 neutrons.

Hope this answers your Q

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5. Identify each of the following as an element, a mixture, or a compound.

VashaNatasha [74]

Answer:

Aluminum foil ~ element

Air ~ mixture

Water ~ compound

Salt Water ~ mixture

Copper Wire ~ element

Steel ~ element

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3 years ago

Which inquiry skill is based on identifying common features?

expeople1 [14]

<span>Classify is the answer hope this helps :)</span>

3 0

3 years ago

The equilibrium expression for a reaction is `"K"_("eq") = ("[H"^+"]"^6)/("[Bi"^(2+)"]"^2["H"_2"S"]^3)` Which of the following c

Nata [24]

Option B is correct

K = Kp /Kr

The given equation indicating, the product containing 6 moles of proton whereas the reactant contains 2 mole of bismuth and 3 mole of hydrogen sulphide.

Hence, in reaction B there are 2 mole of bismuth and 3 mole of hydrogen sulphide reacting to produce 6 moles of proton. whereas the concentration of Bi2S3 is not considered as it is present in solid phase.

4 0

3 years ago

Read 2 more answers

The majority of water molecules moving across plasma membranes by osmosis do so via a process that is most similar to ____.

ValentinkaMS [17]

Answer:

The answer is Facilitated Diffusion

Explanation:

Osmosis is most similar to facilitated diffusion.

Osmosis can be defined as : Osmosis is the movement of water molecules across a semi-permeable membrane, down a concentration gradient from a low concentrated solution into a more concentrated solution.

Facilitated diffusion is defined as: Facilitated diffusion is the flow of molecules requiring the aid of a protein, across a membrane, down a concentration gradient from a low concentrated solution into a more concentrated one.

4 0

2 years ago

30 POINTS! ----- How many moles of oxygen gas are needed to completely react with 145 grams of aluminum? Report your answer with

gladu [14]

First a balanced reaction equation must be established:
$4Al _{(s)} + 3 O_{2} _{(g)}$ → $2 Al_{2} O_{3}$

Now if mass of aluminum = 145 g
the moles of aluminum = (MASS) ÷ (MOLAR MASS) = 145 g ÷ 30 g/mol
= 4.83 mols

Now the mole ratio of Al : O₂ based on the equation is 4 : 3
[4Al + 3 O₂ → 2 Al₂O₃]

∴ if moles of Al = 4.83 moles
then moles of O₂ = (4.83 mol ÷ 4) × 3
= 3.63 mol (to 2 sig. fig.)

Thus it can be concluded that 3.63 moles of oxygen is needed to react completely with 145 g of aluminum.

4 0

3 years ago