Answer:
Option D is correct = -273 °C
Explanation:
Data given:
Temperature of absolute zero
Absolute Zero in Celsius = ?
Solution:
As we know
internationally the temperature of Absolute zero on kelvin scale = 0 K
So to convert Kelvin temperature to degree Celsius formula will used
T(K) = T(°C) + 273
Rearrange the above equation for °C
T(°C) = T(K) - 273 . . . . (1)
Put value in above eq.1
T(°C) = 0 - 273
T(°C) = -273
So,
The absolute zero in °C = -273
so option D is correct
<span>Ksp = 1.2 x 10^-17 = [Zn2+] [OH-]^2
Zn(OH)2 <----> Zn2+ + 2OH-
[Zn2+] = x
[OH-] = 2x
1.2 x 10^-17 = (x) ( 2x)^2 = 4 x ^3
x = 1.4 x 10^-6 M
2x = 2.8 x 10^-6 M
pOH = - log 2.8 x 10^-6 = 5.5
pH = 14 - 5.5 =8.5
i think this is it
</span>
called the Avogadro number
N(A)= 6.02 x 10^23 mol^-1
1 mole of SO3 will contain 6.02 x 10^23 mol^-1 of SO3 molecules.
thus, 1.14moles will contain;
= 1.14mol x [3mol O/1mol SO3] x [6.02 x 10^23
atoms O/1mol O]
= 2.05884 x 10^24 oxygen atoms
= 1.14mol x [1mol S/1mol SO3] x [6.02 x 10^23
atoms O/1mol O]
= 6.8628 x 10^23 sulfur atoms
hope this helps:-)
A solution of an ionic compound that does not totally split
in solution will nearly continually have electrical conductivity lower than
that for a solution of the same concentration of a compound in which all the
ionic bonds do dissociate in the solvent. As opposed to a strong
electrolyte which totally dissociates into detached ions or a non-electrolyte
which doesn't detach at all.
Below are the choices and the answer is 1 and 4.
1. There are differences in molecular size and shape and thus in the strength of dispersion forces.
<span>2. There are differences in the molecular dipoles of the molecules. </span>
<span>3. There is increased hydrogen bonding with an increasing number of hydrogen atoms. </span>
<span>4. There are differences in bonding between atoms within the molecules. </span>
