The volume of 0.125 mole of the gas at the same temperature and pressure 0.30 L
<h3>Data obtained from the question </h3>
- Initial mole (n₁) = 0.82 mole
- Initial volume (V₁) = 2 L
- New mole (n₂) = 0.125 mole
- Pressure = Constant
- Temperature = Constant
- New Volume (V₂) =?
<h3>How to determine the new volume</h3>
The new volume can be obtained as illustrated below
PV = nRT
Divide both side by P
V = nRT / P
Divide both side by n
V / n = RT / P = Constant
Thus,
V₁ / n₁ = V₂ / n₂
2 / 0.82 = V₂ / 0.125
Cross multiply
0.82 × V₂ = 2 × 0.125
Divide both side by 0.82
V₂ = (2 × 0.125) / 0.82
V₂ = 0.30 L
Learn more about ideal gas equation:
brainly.com/question/4147359
#SPJ12
Answer:
742.2 L
Explanation:
First we must find the number of moles of nitroglycerine reacted.
Molar mass of nitroglycerine= 227.0865 g/mol
Mass of nitroglycerine involved = 1×10^3 g
Number of moles of nitroglycerine= 1×10^3g/227.0865 g/mol
n= 4.40361 moles
T= 1985°C + 273= 2258K
P= 1.100atm
R= 0.082atmLmol-1K-1
Using the ideal gas equation:
PV= nRT
V= nRT/P
V= 4.40361× 0.082× 2258/1.1
V= 742 L
Answer:
Reaction is already balanced
Explanation:
The equation in reaction 1 is given as;
CH3COOH + NaHCO3 --> CO2 + H2O + Na+ + CH3COO-
The reaction is already balanced. This is because the umber of atoms of elements in the reactant is equal to that of the products
Carbon
Reactant = 2 + 1 = 3
Product = 2 + 2 = 3
Hydrogen
Reactant = 3 + 1 + 1 = 5
Product = 2 + 3 = 5
Oxygen
Reactant = 2 + 3 = 5
Product = 2 +1 + 2 = 5
Sodium
Reactant = 1
Product = 1
