We have that
<span>Circle 1: center (8, 5) and radius 6
</span><span>Circle 2: center (−2, 1) and radius 2
we know that
the equation of a circle is
(x-h)</span>²+(y-k)²=r²
for the circle 1---------> (x-8)²+(y-5)²=36
for the circle 2---------> (x+2)²+(y-1)²=4
using a graph tool
see the attached figure
Part A)<span>What transformations can be applied to Circle 1 to prove that the circles are similar?
we know that
r1/r2---------> 6/2------> 3
</span><span>
to prove that the circle 1 and circle 2 are similar, the radius of circle 1 </span>must be divided by 3 and translate the center of the circle 1 (10) units to the left and (4) units down
<span>
the answer part A) is
</span>
the radius of circle 1 must be divided by 3 and translate the center of the circle 1 (10) units to the left and (4) units down
Part B) <span>What scale factor does the dilation from Circle 1 to Circle 2 have?
the answer Part B) is
the scale factor is (3/1)</span>
Your answer is C) 1/9
lol I just solved the other answer sorry but people are going to try and take free points so I needed to give an answer to show that someone did something. Hope I helped anyway. You don't need to mark brainliest, but I'd appreciate it if you did.
<h2>-^_^-</h2>
Answer:
f(x)=x/7
Step-by-step explanation:
f(x)=7x
y=7x
x=7y (switch y and x for inverse)
x=7y (isolate y)
x/7=y
The inverse of f(x)=7x is f(x)=x/7
Let
x = first consecutive odd
x + 2 = second consecutive odd
Based on the problem, we equate
x + (x + 2) = 32
Solving for x,
2x + 2 = 32
2x = 32 - 2
2x = 30
x = 30/2
x = 15
and x + 2 = 15 + 2 = 17
Therefore, the integers are 15 and 17.