Answer:
a. True
Explanation:
The three tiers in a three-tier architecture are:
Presentation Tier: Occupies the top level and displays information related to services available on a website. This tier communicates with other tiers by sending results to the browser and other tiers in the network.
Middle Tier: Also called the application tier, logic tier, business logic or logic tier, this tier is pulled from the presentation tier. It controls application functionality by performing detailed processing.
Data Tier: Houses database servers where information is stored and retrieved. Data in this tier is kept independent of application servers or business logic.
Answer:
The most significant issue addressed while ensuring the proper functionality of computer is the working of Operating System.
Explanation:
There are many issues faced while making the computer properly functional. Such as, Memory size, processor speed, software installation etc. while operating system not working properly can cause a significant problem. If operating system is not working properly, the user is unable to use the computer.
So, to make sure the functioning of computer, the significant issue that should be needed to address is Operating System Installation.
The storage that is used to store data in the computer's memory that can be used by a program later when executing instructions is variables.
<h3>What is variables?</h3>
Variables can be defined as the way or process in which data or information are store in a computer memory.
Data or information that may likely change or be altered are often stores in a computer memory storage called variables and this store data can be retrieve later for use by a program when executing instruction on the computer system.
Inconclusion the storage that is used to store data in the computer's memory that can be used by a program later when executing instructions is variables.
Learn more about variables here:brainly.com/question/23931018
Answer:
Let the function be Node* ins(Node *root,int k)
if root node is NULL then return new node with data equal to k.
If the k <root->data
root->left=ins(root->left,k);
else if k >root->data
root->right =ins(root->right,k);
At last return root.
Explanation:
Node is always inserted at the at the leaf node.We will search k in the tree if we hit a the leaf node the new node is inserted as the child of the leaf node.
