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Ira Lisetskai [31]
4 years ago
6

What element in the second period has the largest atomic radius?

Chemistry
1 answer:
madreJ [45]4 years ago
3 0

Answer:

b. lithium

Explanation:

furthest to the left in second period

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Calculate the number of molecules present in 11 moles of H2O.
DedPeter [7]

Answer:

11 \times 6.022 \times  {10}^{23}  \\  = 66.242\times  {10}^{23} \: of \:  \\ water \: molecules

6 0
3 years ago
Calculate the ph of a 0.005 m solution of potassium oxide k2o
Alecsey [184]
First, we have to see how K2O behaves when it is dissolved in water:

K2O + H20 = 2 KOH

According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:

c(KOH) : c(K2O) = 1 : 2

So,

c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)

Now we can calculate pH:

pOH= -log c(OH⁻) = -log 0.01 = 2

pH= 14-2 = 12




3 0
3 years ago
Refrigerators are usually kept at about 5°C, while room temperature is about 20°C. if you were to take an empty sealed 2 liter s
MakcuM [25]

Answer:

c) No, because Celsius is not an absolute temperature scale

Explanation:

converting  5 oC to kelvin which is the absolute temperature scale gives = 273 + 5 = 278 K

and converting 20 oC to kelvin = 20 + 273 = 293 K

the ratio = 278 / 293 = 0.94 approx 1 not 4

8 0
3 years ago
Does anyone now what r.a.c.e mean in science space race what each word stands for
gregori [183]

Answer: Space Race

The informal competition between the United States and the Soviet Union to launch unmanned satellites, send people into space and land them on the Moon

Explanation:

3 0
3 years ago
Determine the pH at the point in the titration of 40.0 mL of 0.200 M H₂NNH₂ with 0.100 M HNO₃ after 100.0 mL of the strong acid
Irina-Kira [14]

Answer:

pH = 1.85

Explanation:

The reaction of H₂NNH₂ with HNO₃ is::

H₂NNH₂ + HNO₃ → H₂NNH₃⁺ + NO₃⁻

Moles of H₂NNH₂ and HNO₃ are:

H₂NNH₂: 0.0400L ₓ (0.200mol / L) = 8.00x10⁻³ moles of H₂NNH₂

HNO₃: 0.1000L ₓ (0.100mol / L) = 0.01 moles of HNO₃

As moles of HNO₃ > moles of H₂NNH₂, all H₂NNH₂ will react producing H₂NNH₃⁺, but you will have an excess of HNO₃ (Strong acid).

Moles of HNO₃ in excess are:

0.01 mol - 8.00x10⁻³ moles = 2.00x10⁻³ moles of HNO₃ = moles of H⁺

Total volume is 100.0mL + 40.0mL = 140.0mL = 0.1400L.

Thus, [H⁺] is:

[H⁺] = 2.00x10⁻³ moles / 0.1400L = 0.0143M

As pH = - log [H⁺]

<h3>pH = 1.85 </h3>
6 0
3 years ago
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