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denpristay [2]
3 years ago
8

Drag each number to the correct location on the equation. Not all numbers will be used.

Mathematics
1 answer:
sveticcg [70]3 years ago
8 0

Answer:

The equation of the hypotenuse line is y = -3·x + 9

Therefore, the correct options are -3 and 9

Step-by-step explanation:

The question asks to fill the boxes

y = _ x + _

We note that the equation is that of a straight line of the form;

y = m·x + c

Where:

m = Slope of the straight line graph and

c = Y intercept, that is the y-coordinate of the point on the line where x = 0

From the graph, we find the slope as follows;

Slope = \frac{y_2 - y_1}{x_2 -x_1} = \frac{(-9) -0}{6-3} = -3

Therefore, m = -3

The y intercept is found by extending the hypotenuse line to the point where it touches the y axes that is at x = 0;

From the graph, it is observed that the line, when extended, touches the y axes at the point y = 9, therefore, c = 9

Hence we have, the equation of the hypotenuse line is y = -3·x + 9.

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2 x (6 divided by 2 + 8) - 4
Artemon [7]

Answer:

18

Step-by-step explanation:

2x (6 divided by 2 + 8) - 4

2x ( 3+8) - 4

2x 11 - 4

22-4

18

8 0
3 years ago
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7-12, in 7&8 trace line m and point m
yKpoI14uk [10]

Answer:

sorry i neeeeeeeeeeeeeed the points

Step-by-step explanation:

5 0
3 years ago
I require assistance with this problem.<br> Solve for X:<br> 5/10 + 1/x = 5/6
BabaBlast [244]

Answer:

x = 3

Step-by-step explanation:

Solve for x:

1/2 + 1/x = 5/6

Bring 1/2 + 1/x together using the common denominator 2 x:

(x + 2)/(2 x) = 5/6

Cross multiply:

6 (x + 2) = 10 x

Expand out terms of the left hand side:

6 x + 12 = 10 x

Subtract 10 x + 12 from both sides:

-4 x = -12

Divide both sides by -4:

Answer:  x = 3

4 0
3 years ago
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Each side of a rhombus is 20 cm long and one of its diagonals is 24 cm in length, find the area of ​​this rhombus?
vodomira [7]

Answer:

AB = 20 CM

OA = 1

__ × 24 cm

2

= 12 cm

AOB = 90 °

OB² == AB² - OA ²

( {20}^{2} ) - ( {12}^{2} ) \\  = 400 - 144 \\  = 256 \\

ob \:  =  \sqrt{256}  = 16 \\ bd \:  = 2 \times ob \\  = 2 \times 16 \\  = 32cm \:  \\

AREA OF ABCD IS

\frac{1}{2 }  \times ac \times bd \\  =  \frac{1}{2}  \times 24 \times 32 \\ 384cm

hope \: its \: helpful \:  \: to \: you \:

6 0
2 years ago
Read 2 more answers
Can someone help me please and explain.
exis [7]
[This question is such you will not understand a thing without your involvement as well. So follow my step and check by yourself]

First plot both functions on graph (this you gotta do yourself and check because only then you will learn)

How you plot the function?

f(x)=-3x³+5x-5

Put y=f(x)

y=-3x³+5x-5➡eqn(1)

So note the corresponding values of y on putting different values of x in that function.

I'll show u:

When x=0,y=-5 [calculate yourself it's easy just put x=0 and find value of y in eqn(1)]

Similarly,

x=1,y=-3

x=2,y=-19

[Similarly put x=-1,-2..and find corresponding y]

So you got points (0,-5),(1,-3),(2,-19)...plot these points and you have successfully plotted f(x).

Same process for plotting function g(x)....at least 6 points must be plotted.

❇After plotting f(x) and g(x):

1)check by yourself if they have same y-intercept (which is the distance between origin and the point of intersection of y-axis and the curve/line)

2) To check if they have same behavior or not,

increase the value of x[ie,1,2,3...] and note the corresponding value of y in function f(x) . Then decrease value of x[ie,-1,-2,-3..] and note corresponding value of y [note that y means function or f(x)]

Suppose f(x) has following end behavior:

When x increases f(x) tends to decrease

and when x decreases f(x) tends to increase

Now find end behavior of g(x) also..and if above end behavior matches with g(x), they will have same end behavior.

3) check by yourself by looking in plotted graphs of f(x) and g(x) whether they have at least one x-intercept or not.

4)g(x) is even function but f(x) is odd function.

So, g(x) is symmetrical over y-axis but f(x) is not.

5) Actually most of the algebraic polynomial functions don't show periodicity(but trigonometric and exponential function do). You can check by yourself by looking in plotted graph. If graph seems to be repeating same behavior it is periodic otherwise not. I am sure the given functions are not periodic. {Plz google periodic function if you want to know more}
3 0
3 years ago
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