Answer:
Answer ::+-6
Step-by-step explanation:
x:3=12:x
or, x/3 = 12/x
Doing cross multiplication,
x^2=36
Putting sqare root on both sides,
x= sqrt. 36
x= +- 6
Therefore x=+-6.
<em>The</em><em> </em><em>clock</em><em> </em><em>says</em><em> </em><em>4</em><em>:</em><em>3</em><em>o</em><em> </em><em>am</em><em>/</em><em>pm</em><em> </em><em>as</em><em> </em><em>big</em><em> </em><em>one</em><em> </em><em>is</em><em> </em><em>at</em><em> </em><em> </em><em>6</em><em> </em><em>and</em><em> </em><em>small</em><em> </em><em>near</em><em> </em><em>4</em>
ah, those are systems you want one variable to cancel out. I would time the bottom equation by -1 so x cancels then u solve for y. then u plug all back in to solve for x.
Answer:
32º
Step-by-step explanation:
Fº-32 ×5/9
5/9Fº-160/9
5/9Fº =160/9
(5Fº)9=9(160)
45Fº=1440
divide both sides by 45
Fº=32
For this case we have the following inequality:
Assuming that "d" is the variable that represents the number of hours worked by Mo during this week, we have that the hours were greater than 11, according to the inequality sign.
So, the correct option is:
Mo worked more than 11 hours this week.
Answer:
Option A
