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3 years ago

Which is the next logical step in balancing the given equation?

2 answers:

8 0

To balance the give n equation, we apply elemtal balance and count each elements per side. There are 2 nitrogens in the left side so there should be 2 moles of NO2. Since there are already 4 moles of O in the right side, there should be 2 moles of O2. Hence answer is a. <span>Place the coefficient 2 in front of oxygen and nitrogen dioxide.</span>

hjlf3 years ago

8 0

Place the coefficient 2 in front of oxygen and nitrogen dioxide.

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A gas at 1.2 atm has a

Papessa [141]

Answer:

1.26 mole

Explanation:

Using ideal gas law

PV=nRT

R= 0.08206

T=273+87=360

1.2×31=n×0.08206×360

37.2 =n × 29.54

n= 1.26 mole

8 0

4 years ago

More accurate dates of the reigns of ancient Egyptian pharaohs have been determined recently using plants

ArbitrLikvidat [17]

King Tut's reign came to an end at 3350 years ago

<h3>Further explanation</h3>

Carbon-14 is a radioactive isotope that can decay. This isotope can be used to determine how long ago an organism died by knowing the ratio from 12C to 14C

Can be formulated

$\tt Nt=No\dfrac{1}{2}^{t/t1/2}$

Or we can use :

$t=-\frac{1}{\lambda }\text{ln}\left(\frac{{N}_{t}}{{N}_{0}}\right)\longrightarrow t=-\frac{1}{\lambda }\text{ln}\left(\frac{{\text{Rate}}_{t}}{{\text{Rate}}_{0}}\right)$

The half-life of C-14, 5730 years, so the decay constant :

$\tt \lambda =\dfrac{\text{ln 2}}{{t}_{1\text{/}2}}=\dfrac{0.693}{\text{5730 y}}=1.21\times {10}^{-4}}$

Assume the initial C-14 activity was 13.6 disintegrations/min/g of C

$\tt t=-\dfrac{1}{\lambda }\text{ln}\left(\dfrac{{\text{Rate}}_{t}}{{\text{Rate}}_{0}}\right)=-\dfrac{1}{1.21\times {10}^{-4}}\text{ln}\left(\dfrac{9.07}{13.6}\right)=\text{3348}\approx 3350~y$

7 0

3 years ago

What type of energy uses turbines

labwork [276]

Answer:

The answer is : D. Wind energy

3 0

3 years ago

The element germanium is a lustrous, hard, grayish-white solid in the carbon group. It is a semiconductor with an appearance sim

stealth61 [152]

Hello!

Based on these facts, we should classify Germanium as a Metalloid.

Metalloids are chemical elements with a mixture of properties from metals and non-metals. Although Germanium has a metallic appearance (typical of metals), it doesn't have the conductive properties of metals, but is a semiconductor. The semiconductive properties of Germanium are used in applications like transistors and chips.

Have a nice day!

4 0

3 years ago

Read 2 more answers

What’s the most abundant isotope of lawrencium

ale4655 [162]

Lawrencium has 10 recognized isotopes. Its most stable is 262Lr, with a half-life of about four hours.

8 0

3 years ago

Read 2 more answers