It will quarter the result. (I think so)
Correct Question:
Which term could be put in the blank to create a fully simplified polynomial written in standard form?
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y3)
Options

Answer:

Step-by-step explanation:
Given
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y%5E3)
Required
Fill in the missing gap
We have that:
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y%5E3)
From the polynomial, we can see that the power of x starts from 3 and stops at 0 while the power of y is constant.
Hence, the variable of the polynomial is x
This implies that the power of x decreases by 1 in each term.
The missing gap has to its left, a term with x to the power of 3 and to its right, a term with x to the power of 1.
This implies that the blank will be filled with a term that has its power of x to be 2
From the list of given options, only
can be used to complete the polynomial.
Hence, the complete polynomial is:

C.√93
A=17
B=14
...........................
Answer:
Option 1.
Step-by-step explanation:
The height of the tide over the time is shown on the graph.
Its a periodic function (sine graph) plotted on a graph in which variables are
Amplitude a = (6-0)/2 = 3
Period = 15-3 = 12
Therefore b = 2π/period = 2π/12 = π/6
horizontal shift = 0
Vertical shift = 3
Since the function starts with negative sign that means its below the x-axis.
So as per standard formula of f(x) = asin(bx+c)+d
option which matches all these parameters is Option 1. 