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Sunny_sXe [5.5K]
2 years ago
11

Plz do it on paper and plz send the work to me plz thank you

Mathematics
1 answer:
Lelu [443]2 years ago
5 0
Its as simple as length times breath there for it is 7/9 times 6/5 which has a common denominator of 45 so now it is 7/45 and 6/45 and then we say how many times did we multiply the denominator to get to 45 and use that number to multiply the numerator so now we have 35/45 and 54/45 and if you times both of them together you get 14/15 as a final answere
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Jamie purchased a DVD that was on sale for 15% off. The sales tax in her county is 5%. Let y represent the original price of the
Triss [41]

Answer:

1.05(0.85y)

Step-by-step explanation:

15% off so .85y and a 5% tax so 1.05(.85y)

6 0
2 years ago
Read 2 more answers
If the car dealer pays 85% of the base price and 75% of the installed options price from the manufacturer,
stira [4]

Answer:

$18,007,50

Step-by-step explanation:

First, you have to calculate the 85% of the base price that the dealer pays for the car:

base price: $18,750

$18,750*85%= $15,937.5

Second, you have to calculate the 75% of the installed options price that the dealer pays:

installed options price= $2,380

$2380*75%= $1,785

Third, you have to add the 85% of the base price plus the 75% of the installed options that the dealer has to pay and you also have to add the destination charge of $285:

$15,937.5+$1,785+$285= $18,007.5

According to this, the dealer has to pay $18,007.5 for the car with a base price of $18,750 and installed options price $2380  including a destination charge of $285.

7 0
3 years ago
Having serious block because of the units The density of mercury is 13.6 g/cm3. What approximate mass of mercury is required to
mart [117]
I would approach the problem like this:

1 oz bottle.............................30cm^3
33 oz bottle.............................xcm^3

in a 33 oz bottle will be x=33*30=990cm^3
density=mm/v
13.6g/cm^3= m/ 990cm^3
m= 13.6 * 990=13464 g
or 13.464 kg in a 33 oz bottle
3 0
2 years ago
Last​ year, a person wrote 126 checks. Let the random variable x represent the number of checks he wrote in one​ day, and assume
Arisa [49]

Answer:  The mean number of checks written per​ day  =0.3452

Standard deviation=0.5875

Variance  =0.3452

Step-by-step explanation:

Given : The total number of checks wrote by person in a year = 126

Assume that the year is not a leap year.

Then  1 year = 365 days

Let the random variable x represent the number of checks he wrote in one​ day.

Then , the mean number of checks wrote by person each days id=s given by :-

\lambda=\dfrac{126}{365}\approx0.3452

Since , the distribution is Poisson distribution , then the variance must equal to the mean value i.e. \sigma^2=\lambda=0.3452

Standard deviation : \sigma=\sqrt{0.3452}=0.5875372328\approx0.5875

6 0
3 years ago
Please help I will give brainliest.
salantis [7]

Answer:

Multiply the numbers then Add on both sides then simplify

Step-by-step explanation:

8 0
2 years ago
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