Good morning Mr. William I wanted to ask you if it is still possible to change an elective class
Answer:
<h2>1 < x < 6 ⇒ x ∈ (1, 6)</h2>
Step-by-step explanation:
3x - 8 > -5 <em>add 8 to both sides</em>
3x > 3 <em>divide both sides by 3</em>
x > 1
2x - 7 < 5 <em>add 7 to both sides</em>
2x < 12 <em>divide both sides by 2</em>
x < 6
From x > 1 and x < 6 we have the solution 1 < x < 6 ⇒ x ∈ (1, 6)
Split it into 7 triangles. Half-base of each is 2 so the distance of center to the midpoint of the base is (Pythagoras) square root of (4.62 - 22) = 4.162 triangle is this times 2, and with 7 triangles multiply also by 7 to get an approximate area of 58 sq in.
If we start with 6 and 8, we can break 6 up into 2*3 and 8 into 2*2*2, thus getting a prime factorization of 2*2*2*2*3, or 2^4 *3.
If we begin with 4 and 12, 4 breaks into 2*2 and 12 into 2*2*3, so the prime factorization of 48 is still 2^4 *3.
The starting factors do not matter, since the answer comes out to be the same. There is exactly one correct answer- it doesn't matter how it's found.
Hope this helps! :)
