1. For this question, the adjective small must be percepted in a relative sense. This is because it is not the smallest ion (that would be hydrogen). It could be that the antimony and beryllium ions are smaller compared to their neutral forms. This is because they donate electrons when ionized. As a result, the electrons are reduced, so does the electron cloud which makes the radius much smaller.
2. The periodic table is arranged in terms of increasing atomic number. For neutral atoms, the number of protons (atomic number) is equal to the number of electrons. So, the farther we go down the table, the higher the atomic number. The higher the atomic number, the bigger the electron cloud which makes the atomic radius bigger. Because by definition, atomic radius is the length from the nucleus to the farthest electron from the nucleus.
Balanced chemical reaction: 2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g).
KOH is inorganic compound p<span>otassium hydroxide, a strong base.
H</span>₂ is hydrogen gas.
In balanced chemical reaction number of atoms on both side of chemical reaction must be same. There are two potassium atoms, four hydrogen atoms and two oxygen atoms on both side of reaction.
Answer:
https://youtu.be/3zmeVamEsWI
Explanation:
It is defined as the ratio of moles of one substance to the moles of another substance in a balanced equation. ... Mole ratios are the central step in performing stoichiometry because they allow us to convert moles of one substance to moles of another substance.
The statement above is true. He conducted the oil-drop experiment which lead him to determine the charge of the electron. He suspended charged droplets into an oil which is in between two electrodes and balancing the upward force with the downward forces.
Answer:
The answer to your question is
1.-Fe₂O₃
2.- 280 g
3.- 330 g
Explanation:
Data
mass of CO = 224 g
mass of Fe₂O₃ = 400 g
mass of Fe = ?
mass of CO₂
Balanced chemical reaction
Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂
1.- Calculate the molar mass of Fe₂O₃ and CO
Fe₂O₃ = (56 x 2) + (16 x 3) = 160 g
CO = 12 + 16 = 28 g
2.- Calculate the proportions
theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90
experimental proportion Fe₂O₃ / CO = 400/224 = 1.78
As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.
3.- 160 g of Fe₂O₃ --------------- 2(56) g of Fe
400 g of Fe₂O₃ --------------- x
x = (400 x 112) / 160
x = 280 g of Fe
4.- 160 g of Fe₂O₃ --------------- 3(44) g of CO₂
400 g of Fe₂O₃ -------------- x
x = (400 x 132)/160
x = 330 gr
