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weeeeeb [17]
3 years ago
11

Question 4 of 20

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
6 0

Answer:

D

Explanation:

Reacting with acid is the only chemical property out of the 4 options. The rest are physical

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students used a balance and a graduated cylinder to collect the data shown in table 7. calculate the density of the sample. if t
Licemer1 [7]

Answer:

              Percentage error  =  1.88 %

Solution:

Data Given:

                 Mass of Sample  =  20.46 g

                 Volume of Sample  =  43.0 mL - 40.0 mL  =  3.0 mL

Formula Used:

                 Density  =  Mass / Volume

Putting values,

                 Density  =  20.46 g /  3.0 mL

                 Density  =  6.82 g.mL⁻¹

Percentage Error:

                 Experimental Value  =  6.82 g.mL⁻¹

                 Accepted Value  =  6.95 g.mL⁻¹

                 = 6.82 g.mL⁻¹ / 6.95 g.mL⁻¹ × 100  =  98.12 %

                 Percentage Error  =  100 % - 98.12 %

                Percentage error  =  1.88 %

3 0
3 years ago
26.6 mL of 2.50 M stock solution of sucrose is diluted to 50.0 mL. A 16.0 mL sample of the resulting solution is then diluted to
frozen [14]

Answer:

In the final solution, the concentration of sucrose is 0.126 M

Explanation:

Hi there!

The number of moles of solute in the volume taken from the more concentrated solution will be equal to the number of moles of solute in the diluted solution. Then, the concentration of the first solution can be calculated using the following equation:

Ci · Vi = Cf · Vf

Where:

Ci = concentration of the original solution

Vi = volume of the solution taken to prepare the more diluted solution.

Cf = concentration of the more diluted solution.

Vf = volume of the more diluted solution.

For the first dillution:

26.6 ml · 2.50 M = 50.0 ml · Cf

Cf = 26.6 ml · 2.50 M / 50.0 ml

Cf = 1.33 M

For the second dilution:

16.0 ml · 1.33 M = 45.0 ml · Cf

Cf = 16.0 ml · 1.33 M / 45.0 ml

Cf = 0.473 M

For the third dilution:

20.0 ml · 0.473 M = 75.0 ml · Cf

Cf = 20.0 ml · 0.473 M / 75.0 ml

Cf = 0.126 M

In the final solution, the concentration of sucrose is 0.126 M

7 0
3 years ago
State the postulate of Bohr theory
KengaRu [80]

Answer:

Bohr's model of the hydrogen atom is based on three postulates:

1) An electron moves around the nucleus in a circular orbit,

2) An electron's angular momentum in the orbit is quantised,

3) The change in an electron's energy as it makes a quantum jump from one orbit to another is always accompanied by the emission or absorption of a photon. Bohr's model is semi-classical because it combines the classical concept of electron orbit (postulate 1) with the new concept of quantisation ( postulates 2 and ).

4 0
3 years ago
The addictive power of nicotine is enhanced by which of the following chemicals?
ArbitrLikvidat [17]
The correct answer is A. Ammonia.
5 0
3 years ago
It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0?C to 24.3?C. What is the specific heat for
svet-max [94.6K]

Answer:

c = 0.377 J/g.°C

c = 0.2350 J/g.°C

J = 27.3 J

Explanation:

We can calculate the heat (Q) absorbed or released by a substance using the following expression.

Q = c × m × ΔT

where,

c: specific heat

m: mass

ΔT: change in the temperature

<em>It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0°C to 24.3°C. What is the specific heat for the metal? Express your answer numerically, in J/g.°C</em>

Q = c × m × ΔT

49.0 J = c × 11.5 g × (24.3°C - 13.0°C)

c = 0.377 J/g.°C

<em>The molar heat capacity of silver is 25.35 J/mol.°C. How much energy would it take to raise the temperature of 11.5g of silver by 10.1°C? Express your answer numerically, in Joules. What is the specific heat of silver?</em>

<em />

The molar mass of silver is 107.87 g/mol. The specific heat of silver is:

\frac{25.35J}{mol.\° C} .\frac{mol}{107.87g} =0.2350J/g.\° C

Q = c × m × ΔT

Q = (0.2350 J/g.°C) × 11.5 g × 10.1°C = 27.3 J

5 0
3 years ago
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