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Usimov [2.4K]
3 years ago
6

What is the molarity of a 2.4-liter solution containing 124 grams of HF?

Chemistry
2 answers:
ioda3 years ago
7 0
Molar mass:

HF = 1 + 19 = 20.0 g/mol

Number of moles :

124 / 20.0 =>  6.2 moles

Volume = 2.4 L

M = n / V

M = 6.2 / 2.4

M = 2.6 M

Answer A

hope this helps!

Romashka-Z-Leto [24]3 years ago
7 0
The Answer is A as you said:

Molarity = \frac{no. of moles}{volume}

moles of HF = <span>\frac{mass}{molar mass}
                    = </span>\frac{124}{(1 + 19)}
                    = 6.2 mol

∴  molarity of HF = \frac{6.2 mol}{2.4  dm^{3} }
                           = 2.58 M
                           ≈ 2.6 M
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494.1 kPa

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36.14 = 22.8P2/311.7

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3 0
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atoms in compounds :

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<u />

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