2KClO3 --> 2KCl + 3O2
3 moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose.
Answer:
MgI₂, MgO, PbI₄, PbO₂
Explanation:
For an ionic compound to be formed, it must be neutral, that is the total positive charge must be equal to the total negative charge.
Mg²⁺ and I⁻: The neutral ionic compound requires 1 Mg²⁺ and 2 I⁻ and the resulting empirical formula is MgI₂.
Mg²⁺ and O²⁻: The neutral ionic compound requires 1 Mg²⁺ and 1 O²⁻ and the resulting empirical formula is MgO.
Pb⁴⁺ and I⁻: The neutral ionic compound requires 1 Pb⁴⁺ and 4 I⁻ and the resulting empirical formula is PbI₄.
Pb⁴⁺ and O²⁻: The neutral ionic compound requires 1 Pb⁴⁺ and 2 O²⁻ and the resulting empirical formula is PbO₂.
Answer:
V₂ = 1.41 L
Explanation:
Given data:
Initial temperature = 35°C (35 +273.15 K = 308.15 K)
Initial volume = 1.5 L
Final temperature = 17°C (17+273.15 K = 290.15 K)
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 1.5 L × 290.15 K / 308.15 k
V₂ = 435.23 L.K / 308.15 k
V₂ = 1.41 L
There are two in the first ring leaving only six out of eight to go on the next