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3 years ago

7

I think the answer is y=8x but I’m not sure and neither are my parents. My parents told me to look it up but I can’t find any he

lp other than this. Please answer soon!

1 answer:

Ugo [173]3 years ago

5 0

Y = 8x Yea that’s right

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alukav5142 [94]

The answer is (1,11).

5 0

3 years ago

Read 2 more answers

Pleaseee helppp with thisss asappp

Hoochie [10]

We are given with a equation of Circle and we need to find it's radius and it's equation in standard form . But , let's recall , the standard equation of a circle is ${\bf (x-h)^{2}+(y-k)^{2}=r^{2}}$ where <em>(h,k)</em> is the centre of the circle and radius is <em>r</em> . Proceeding further ;

${:\implies \quad \sf x^{2}+12y+22x+y^{2}-167=0}$

Collecting <em>x</em> terms , y terms and transposing the constant to RHS ;

${:\implies \quad \sf (x^{2}+22x)+(y^{2}+12y)=167}$

Now , as in standard equation their is a whole square , so we need to develop a whole square in LHS , for which we will use completing the square method , as coefficient of x² and y² is 1 , so adding 121 and 36 to LHS and RHS .

${:\implies \quad \sf (x^{2}+22x+121)+(y^{2}+12y+36)=167+121+36}$

${:\implies \quad \sf (x+11)^{2}+(y+6)^{2}=324\quad \qquad \{\because a^{2}+2ab+b^{2}=(a+b)^{2}\}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{\{x-(-11)\}^{2}+\{y-(-6)\}^{2}=(18)^{2}}}}$

On comparing this with the standard equation , we got our centre at <em>(-11,-6)</em> and radius is <em>18 units </em>

8 0

1 year ago

Help please help I need help please like pretty please btw this is on mobile

pav-90 [236]

Is just their difference

$\bf 1-\cfrac{3}{8}\implies \cfrac{1}{1}-\cfrac{3}{8}\impliedby \textit{our LCD is 8}\implies \cfrac{8-3}{8}\implies \cfrac{5}{8}$

3 0

3 years ago

What is the net change of F(x)=3x-2;x=2,x=3

sattari [20]

I hope this helps you

x=3

f (3)= 3.3-2

f (3)= 9-2

f (3)= 7

5 0

3 years ago

The function f(t)=1900(1. 4)^t

kotykmax [81]

Answer:

Increasing by 40%

Step-by-step explanation:

This is a exponentional function. The format for this type of function is a(b)^x. So "a" is your initial value, and "b" is the rate. Now let's think to ourselves what times what is still equal to the same thing? That is 1. But in our question, we have 1.4. So we are increasing by 0.4, or 40%.

4 0

1 year ago