A) Possible outcomes are ...
(1, 3), (1, 4), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)
for a total of 7 out of 36 outcomes that match your requirements.
p(3 < sum ≤ 5) = 7/36
B) Possible outcomes are ...
(6, 1), (6, 3), (6, 5), (1, 6), (3, 6), (5, 6)
for a total of 6 out of 36 outcomes that match your requirements.
p(6 and odd) = 6/36 = 1/6
Answer:
3/x=y
Step-by-step explanation:
if not am sorry
Answer:
Option B False
Step-by-step explanation:
we know that
The <u>Cavalieri's principle</u> states that if two or more figures have the same cross-sectional area at every level and the same height, then the figures have the same volume
therefore
The cross-sectional area at every level must be the same
so
The statement is False
Answer:
Area of the resulting rectangle = 23.375 inch²
Step-by-step explanation:
After 1 fold width or length reduces to half.
Area = Length x width
So after 1 fold area will reduce to half.
So we have
Initial area = 8.5 x 11 = 93.5 inch²
Here the paper were folded completely in half, length is reduced to half and width reduced to half, that is
Number of folds = 2
Area after 2 folds = 23.375 inch²
Area of the resulting rectangle = 23.375 inch²
Answer:
The volume of the glass is 217.8 cm³
Step-by-step explanation:
If the glass were initially 4/7 full, that means 3/7 of the volume is still available to hold more juice.
Let v represent the volume of the glass.
Then (3/7)v + 70 cm³ = (3/4)v.
We need to solve this for v.
Here the LCD is 28. Thus,
(3/7)v + 70 cm³ = (3/4)v → (12/28)v + 70 cm³ = (21/28)v.
Subtracting (12/28)v from both sides, we get:
70 cm³ = (9/28)v.
We can isolate v by mult. both sides by the inverse of 9/28, which is 28/9:
(28/9)(70 cm³) = v
The volume of the glass is 217.8 cm³
