The three numbers are 12, 18 and 24
Arithmetic progression
Let the 3 number in arithmetic progression be:
a-d, d, a+d ...
If their sum is 3, then;
a-d+d+a+d = 3
2a + d = 3 ........... 1
If the sum of their squares is 11, then;
(a-d)² + d² + (a+d)² = 11
a²-2ad+d²+d²+a²+2ad+d² 11
2a²+3d² = 11 ....... 2
Solving the equations simultaneously, d = 6 and a = 12
First-term = 12
second term = 18
Thirs term = 24
Hence the three numbers are 12, 18 and 24
Hope this helps you!!!!!! :D
Answer:
i think its infinite solutions
Step-by-step explanation:
A) the answer is A) 0 the answer is 0
Answer:
Purchases greater than 66.67 dollars should use coupon 2, while purchases between 20 dollars and 66.67 should use coupon 1.
Step-by-step explanation:
Coupon 1 must be used as long as those 10 dollars represent more money than 15% of coupon 2.
For example, if the purchase is the minimum of $ 20, 10 dollars represents half of the purchase, therefore in this case it is better to use coupon 1.
In this case, coupon 2 would only be a discount of 3 dollars (20 * 0.15).
So when from what value would it be better to use coupon 2, it would have to be calculated when it is worth more than 10 dollars.
10 = x * 0.15
x = 10 / 0.15
x = 66.67
That is to say that from the purchases greater than 66.67 dollars, coupon 2 would have a discount equivalent to 10 dollars or more.
Answer:
1. 3.
Step-by-step explanation:
The answer to tx2x365 is 730t so when you solve the others you also get 730t
