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Kay [80]
3 years ago
6

In △ABC, AB=BC=29, and AC=42. What is the area of △ABC?

Mathematics
1 answer:
Savatey [412]3 years ago
6 0

Answer:

420 unit^2.

Step-by-step explanation:

Use  the formula area = √(s(s-a)(s-b)(s-c)   where s = the semi-perimeter and ab and c are the 3 sides. (it is called Heron's Formula).

s = (29+29+42)/ 2

= 100/2

= 50.

Area = √50(50-29)(50-29(50-42)

= √176400

= 420.

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