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wariber [46]
3 years ago
9

In ΔEFG, g = 4.3 cm, e = 9.1 cm and ∠F=116°. Find the length of f, to the nearest 10th of a centimeter.

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

11.6

Step-by-step explanation:

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Answer:

The product is 1.4993772e+15.

Step-by-step explanation:

Thanks for the points! Brainliest? Thanks!

5 0
2 years ago
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MCR3U1 Culminating 2021.pdf
11111nata11111 [884]

Answer:

(a) y = 350,000 \times (1 + 0.07132)^t

(b) (i) The population after 8 hours is 607,325

(ii) The population after 24 hours is 1,828,643

(c) The rate of increase of the population as a percentage per hour is 7.132%

(d) The doubling time of the population is approximately, 10.06 hours

Step-by-step explanation:

(a) The initial population of the bacteria, y₁ = a = 350,000

The time the colony grows, t = 12 hours

The final population of bacteria in the colony, y₂ = 800,000

The exponential growth model, can be written as follows;

y = a \cdot (1 + r)^t

Plugging in the values, we get;

800,000 = 350,000 \times (1 + r)^{12}

Therefore;

(1 + r)¹² = 800,000/350,000 = 16/7

12·㏑(1 + r) = ㏑(16/7)

㏑(1 + r) = (㏑(16/7))/12

r = e^((㏑(16/7))/12) - 1 ≈ 0.07132

The  model is therefore;

y = 350,000 \times (1 + 0.07132)^t

(b) (i) The population after 8 hours is given as follows;

y = 350,000 × (1 + 0.07132)⁸ ≈ 607,325.82

By rounding down, we have;

The population after 8 hours, y = 607,325

(ii) The population after 24 hours is given as follows;

y = 350,000 × (1 + 0.07132)²⁴ ≈ 1,828,643.92571

By rounding down, we have;

The population after 24 hours, y = 1,828,643

(c) The rate of increase of the population as a percentage per hour =  r × 100

∴   The rate of increase of the population as a percentage = 0.07132 × 100 = 7.132%

(d) The doubling time of the population is the time it takes the population to double, which is given as follows;

Initial population = y

Final population = 2·y

The doubling time of the population is therefore;

2 \cdot y = y \times (1 + 0.07132)^t

Therefore, we have;

2·y/y =2 = (1 + 0.07132)^t

t = ln2/(ln(1 + 0.07132)) ≈ 10.06

The doubling time of the population is approximately, 10.06 hours.

8 0
3 years ago
. If m 4 = 105, then what is m 8?
polet [3.4K]
I believe the answer is 210 because 1m= 26.25 and that x's 8= 210


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Answer:

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Step-by-step explanation:

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3 years ago
In Ryan coorporation the first shift produced 5 1/2 times as many lightbulbs as the second shift. if the total lightul.bs produc
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Answer:

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  shift 1 : shift 2 = 5.5 : 1 = 11 : 2

so, the production on shift 1 as a ratio to the total is ...

  shift 1 : total = 11 : (11+2) = 11 : 13

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  (11/13)(16,250 bulbs) = 13,750 bulbs . . . . first shift

and the second shift produced ...

  (2/13)(16,250 bulbs) = 2,500 bulbs . . . . second shift

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Of course, once you have one of the numbers, you can also find the other by using the 5.5 factor or by subtracting from total production.

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3 years ago
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