In physics, work is equal to the product of force and distance, given that the direction of force is the same with the direction of the distance.
W = Fd
The total force is
F = 1,700 N + 500 N = 2,200 N
Now, if the question is the work needed to lift the barbell from the ground, the distance would be 2 m. Hence, the work would be
W = (2,220 N)(2 m) = 4,400 N·m or 4,400 J
Answer:
<h2>FALSE</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
order of PEMDAS
- parentheses
- exponent
- multiplication or
- division
- addition
- subtraction
<h3>let's solve:</h3><h2><u>L.</u><u>H.S</u><u>=</u></h2>
- <u>
</u> - <u>
</u>
<h2><u>≠R.H.S</u></h2>
therefore
<h3>the equality is false</h3>
D. -15
All I did was plug the numbers in
Answer:
Value of f (Parapedicular) = 7√6
Step-by-step explanation:
Given:
Given triangle is a right angle triangle
Value of base = 7√2
Angle made by base and hypotenuse = 60°
Find:
Value of f (Parapedicular)
Computation:
Using trigonometry application
Tanθ = Parapedicular / Base
Tan60 = Parapedicular / 7√2
√3 = Parapedicular / 7√2
Value of f (Parapedicular) = 7√2 x √3
Value of f (Parapedicular) = 7√6
