The answer is

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Remember to combine like terms.
Hop this helps. c:</span></span>
Answer:
Gym A
Step-by-step explanation:
A linear relationship is a relationship of the form y = mx + b, where y and x are the linear variables, m is the rate of change and b is the value of y when x = 0.
Gym A:
Let x represent the month and y represent the total cost for the gym. From the table, we can represent the values in the form (x, y) as (1,70), (2, 90) and (3, 110). We can find the relationship between x and y using the formula:

Gym B:
We can represent the values from the table as (1,55), (2, 80) and (3, 105). We can find the relationship between x and y using the formula:

Hence gym A would cost less ($250 < $280)
(a+a+6)*2.5=345
2a+6=138
a=132/2
a=66 mph
a+6=66+6=72 mph
Speed of the first car is 72 mph
You can multiply 0.129 and 0.3 by 10 each to make it a little easier to see what to do.
0.129 / 0.3 = 1.29 / 3
Simple long division will take you to 0.43