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Neko [114]
3 years ago
7

What is the reciprocal of -1/9 and the opposite of -1 / 9

Mathematics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

reciprocal is -9

opposite is 1/9

hope this helps

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{x + y = 2
Mila [183]

1) I put them in two separate brakets.

2) I solved it by equating both of them.

7 0
2 years ago
Read 2 more answers
Jake can mulch a garden in 30 minutes. together, jake and ross can mulch the same garden in 16 minutes. how much time t, in minu
Gelneren [198K]

"Jake can mulch a garden in 30 minutes." So, for 1 min Jake can mulch 1/30 part of a garden.

Ross can mulch the park for x minutes. So, for 1 min Jake can mulch 1/x part of a garden.

If they work together, for 1 min they will mulch (1/30 + 1/x) part of the garden.

At the same time, we know, that of they work together they can mulch the garden in 16 min, so for 1 min they will mulch 1/16 part of the garden.

Now, we can write an equation

\frac{1}{30}  + \frac{1}{x} = \frac{1}{16}  \\ \\ \frac{1}{x} = \frac{1}{16} - \frac{1}{30}  \\ \\ \frac{1}{x} =\frac{30-16}{16*30}  \\ \\ \frac{1}{x} =\frac{14}{16*30}  \\ \\x=\frac{16*30}{14}

x≈34.3 (min)

8 0
3 years ago
A, b and c are the sides of a right triangle, where side a is across from angle a, side b is across from angle b, and side c is
Vera_Pavlovna [14]
<span>Find missing length :
</span>
a² + b² = c²
c² = 19² + 34²
c² = 1517
c = √1517
c = 38.95 units.


Find missing angle A:

\dfrac{a}{\sin(a)} =  \dfrac{c}{\sin(c)}

\dfrac{19}{\sin(a)} =  \dfrac{38.95}{\sin(90)}

\sin(a) = 0.488

a = sin^{-1} (0.488)

a = 29.2 \textdegree


Find Missing B:

\dfrac{b}{\sin(b)} = \dfrac{c}{\sin(c)}

\dfrac{34}{\sin(b)} = \dfrac{38.95}{\sin(90)}

\sin(b) = 0.873

b = sin^{-1}(0.873)

b = 60.8 \textdegree


Answer: Missing length =  38.95 units ; Missing angles =  29.2°  and  60.8° 

8 0
3 years ago
What is-18+2y is greater then or equal to -13 written in slope intercept form?
olya-2409 [2.1K]

Answer:

y=2.5

Step-by-step explanation:

5 0
3 years ago
H(x)=-x+ 5g(x)=-3x – 2Find (h/g)(x)
Neko [114]

Find (h/g)(x);

\begin{gathered} h(x)=-x+5 \\ g(x)=-3x-2 \\ (\frac{h}{g})(x)=\frac{-x+5}{-3x-2} \end{gathered}

5 0
1 year ago
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