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Neko [114]
4 years ago
7

What is the reciprocal of -1/9 and the opposite of -1 / 9

Mathematics
1 answer:
tiny-mole [99]4 years ago
8 0

Answer:

reciprocal is -9

opposite is 1/9

hope this helps

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Write five expressions that are equivalent to 20x+100
Phoenix [80]
4(5x+25)
5(4x+20)
10(2x+10)
2(10x+50)
20(x+5)

hope this helps
4 0
3 years ago
You estimate that a baby pig weighs 21 lbs but it weighs 28 lbs what is the percent of error
lbvjy [14]
Your estimate of the baby pig's weight is 2 pounds. However the actual weight of it is only 16 pounds.
Let's solve for the percentage error of this.
=> 20 - 16 = 4 pounds
=> 4 / 16 = 0.25
=> 0.25 * 100% = 25%
Thus, you added 25% of the baby pig's weight
3 0
3 years ago
Read 2 more answers
HELP ME PLEASE IM TIMED ILL MAKE U BRAINLIEST
Vadim26 [7]

Answer:

B

Step-by-step explanation:

The answer is B, -12.

Please give me brainliest.

-12^2 --> -144

-144+144 = 0

Therefore, the answer is B, -12.

3 0
3 years ago
Solve for u.<br> 36 – 9u = 27
strojnjashka [21]

Answer:

u = 1

Step-by-step explanation:

First, we can use inverse operations to help.

27 + 9u = 36

Next, we can start replacing u with numbers to find which number fits in u.

27 + 9(1) = 36

27 + 9(2) ≠ 36

27 + 9(3) ≠ 36

Now, we know that u = 1

8 0
3 years ago
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
3 years ago
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