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vazorg [7]
3 years ago
5

The altitude to the hypotenuse of a right triangle divides the hypotenuse into 15 inches and 30 inch segments. Explain or show h

ow to find the exact length of the altitude including the correct value. Then explain or show how to find the length of each leg including the correct values.
Mathematics
1 answer:
e-lub [12.9K]3 years ago
8 0

9514 1404 393

Answer:

  CX = 15√2 inches

  BC = 15√3 inches

  AC = 15√6 inches

Step-by-step explanation:

In this geometry, all of the triangles are similar:

  ΔABC ~ ΔACX ~ ΔCBX

Corresponding segments are proportional in similar triangles, so we have ...

  AX/CX = CX/BX = (long leg)/(short leg)

Filling in the numbers, we get

  30/CX = CX/15

  CX² = 15×30

  CX = 15√2 . . . . . exact length of the altitude (inches)

__

Similarly, we can form proportions with the legs:

  AB/BC = CB/BX

  BC² = (BX)(AB) = (45)(15)

  BC = 15√3 . . . inches

and

  AC/AB = AX/AC

  AC² = (AX)(AB) = (30)(45)

  AC = 15√6 . . . inches

_____

<em>Additional comment</em>

You may notice that each of the segments we're interested in is the root of a product involving segments of the hypotenuse. This "root of a product" is called the geometric mean. Here, the three geometric mean relations are ...

  altitude = geometric mean of hypotenuse segments

  short side = geometric mean of short segment and whole hypotenuse

  long side = geometric mean of long segment and whole hypotenuse

__

Strictly speaking the geometric mean is the n-th root of the product of n items. Here, there are only 2 items, so it is the square root of their product.

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