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Ulleksa [173]
3 years ago
13

Consider the equation:

Mathematics
1 answer:
monitta3 years ago
7 0
<h3>Answers: a = 10, b = 0</h3>

(b can be anything you want as long as its not -4)

======================================================

Work Shown:

Note how ax+b looks really similar to mx+b. All that is different is the slope m is replaced with the letter 'a'.

On the left side, 10x-4 is in the form mx+b with m = 10 as the slope. If we made a = 10, then the slope of the right side would also be 10 and we'd have parallel lines as long as b is not -4.

If b = -4 along with a = 10, then we'd have 10x-4 on the right hand side. This leads to infinitely many solutions.

If b is anything but -4, and a = 10, then we have two parallel lines with no solutions since parallel lines never cross. I'm picking b = 0 since 0 is the easiest number to pick on. You can pick anything you want (as long as its not -4 of course) for the value of b.

You might be interested in
A line passes through the point (-1,-5) and has a slope of -5.
Anna71 [15]
<h3>hello!</h3>

We're given a point that the line intersects and its slope.

Let's use Point-slope:-

\boxed{y-y1=m(x-x1)}

y1 = -5

m=-5

x1=-1

\boxed{y-(-5)=-5(x-(-1)}

\boxed{y+5=-5(x+1)}

Convert to slope-intercept:-

\boxed{y+5=-5x-5}

\boxed{y=-5x-5-5}

Finally,

\bigstar{\boxed{\pmb{y=-5x-10}}

<h3>note:-</h3>

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

5 0
1 year ago
Identify the asymptotes and state the end behavior of the function f(x)=5x/x-25
AnnyKZ [126]

Using it's concepts, it is found that for the function f(x) = \frac{5x}{x - 25}:

  • The vertical asymptote of the function is x = 25.
  • The horizontal asymptote is y = 5. Hence the end behavior is that y \rightarrow 5 when x \rightarrow \infty.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity. They also give the end behavior of a function.

In this problem, the function is:

f(x) = \frac{5x}{x - 25}

For the vertical asymptote, it is given by:

x - 25 = 0 -> x = 25.

The horizontal asymptote is given by:

y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = 5

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

8 0
1 year ago
Identify the initial amount a and the growth factor b in the exponential function.f(t)=1.4^t
vaieri [72.5K]
Initial amount is when no change has happened or when t=0
that iniital amoun tis 1
the growth factor
welll, it grows by 40% each time of previous times

I would say growth factor of 1.4


f(x)=a(b)^t
f(t)=1(1.4)^t
initial amount is 1
grouth factor is 1.4
6 0
3 years ago
How would you graph the result of -3 + 5 as a point on the number line?
almond37 [142]
It would be two places to the right of 0 because -3+5=2
6 0
2 years ago
62 is divisible by which of the following numbers
SVEN [57.7K]

Answer:

D.

Step-by-step explanation:

4 0
2 years ago
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