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Ulleksa [173]
3 years ago
13

Consider the equation:

Mathematics
1 answer:
monitta3 years ago
7 0
<h3>Answers: a = 10, b = 0</h3>

(b can be anything you want as long as its not -4)

======================================================

Work Shown:

Note how ax+b looks really similar to mx+b. All that is different is the slope m is replaced with the letter 'a'.

On the left side, 10x-4 is in the form mx+b with m = 10 as the slope. If we made a = 10, then the slope of the right side would also be 10 and we'd have parallel lines as long as b is not -4.

If b = -4 along with a = 10, then we'd have 10x-4 on the right hand side. This leads to infinitely many solutions.

If b is anything but -4, and a = 10, then we have two parallel lines with no solutions since parallel lines never cross. I'm picking b = 0 since 0 is the easiest number to pick on. You can pick anything you want (as long as its not -4 of course) for the value of b.

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Let X have the probability mass function P(X = −1) = 1 2 , P(X = 0) = 1 3 , P(X = 1) = 1 6 Calculate E(|X|) using the approaches
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Answer:

Step-by-step explanation:

From the given information:

Note that the possible values of Y are 0 and 1 because;

y = 0 if X = 0 and y = 1 if X = ±1

∴

P(Y =0) = P(X = 0) =\dfrac{1}{3}

P(Y = 1) = P(X = -1  \ or \ 1) \\ \\ = P(X = -1) + P(X = 1)

= \dfrac{1}{2}+ \dfrac{1}{6}

=\dfrac{3+1}{6}

= \dfrac{2}{3}

b)

E(|X|) = \sum |x| P(X=x) = ( 1 \times \dfrac{1}{2}) + ( 0\times \dfrac{1}{3}) + ( 1 \times \dfrac{1}{6})

= \dfrac{2}{3}

7 0
3 years ago
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Answer:

-3+(2+4x)

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5 0
4 years ago
What is required in a proportional relationship that is not required nof a general linear relationship?
olchik [2.2K]
<span>Pertains to y-intercept is then 0.</span>
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What is the value of b?<br><br><br><br> 13.17 - b = 8.76
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4.41

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13.17 - 8.76 = 4.41
8 0
3 years ago
Read 2 more answers
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<span>A. Find the complement of the angle shown 

90 - 52 = 38

</span><span>B. Find the supplement of the angle shown. 

180 - 52 = 128

hope that helps</span>
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