All categories

3 years ago

Consider f(x)=2x3 and g(x)=/3x-1/find each value. f(1)-g(2)

Mathematics

1 answer:

Readme [11.4K]3 years ago

6 0

2(1)3=6 (f)
3(2)-1= 5 (g)
6-5=1 so the answer is 1

You might be interested in

Which of the following statements is correct?

Montano1993 [528]

Answer:

Systems of Equations often have infinite solutions.

Step-by-step explanation:

I don't know if there are 7 answers or what

5 0

2 years ago

The APR of Percy’s savings account is 4.4%, and interest is compounded monthly. If the principal in Percy’s savings account were

lutik1710 [3]

Answer:$11,389.39

Step-by-step explanation:

(Apex)

8 0

3 years ago

Please Help!!! Determine the range of the following graph:

ELEN [110]

Answer:

[-1, 6)

General Formulas and Concepts:

Algebra I

Reading a coordinate plane

Algebra II

Range is the set of y-values that are outputted by function f(x)
Interval Notation - [Brackets] denote inclusion and (Parenthesis) denote exclusion

Step-by-step explanation:

According to the graph, our y-values span from -1 to 6. Since -1 is a closed dot, it is inclusive. Since 6 is an open dot, it is exclusive:

Range would then be [-1, 6).

5 0

3 years ago

Find the value of z please help

Elza [17]

z + 93 = 180

z = 87

Answer z = 87

Here are the answer for x and y, in case you need them.

x = 2* 93 - 112

x = 186 - 112

x = 74

y = 2 * 80 - x

y = 160 - 74

y = 86

6 0

3 years ago

Read 2 more answers

Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

Fudgin [204]

A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
$\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac ab$

b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac ab$

The other direction can be proved by following the manipulations in the reverse order.

7 0

3 years ago