Answer:
There were 333 seniors in 1990
153 seniors had jobs in 2010.
Step-by-step explanation:
Let the number of high school seniors in 1990 = x
75% of x had jobs in 1990
In 2010 there were 50 more seniors. That is, the number of seniors is x+50.
40% of (x+50) had jobs in 2010.
Total number of jobs in both years = 403.
\[0.75 * x + 0.4 * (x + 50) = 403\]
\[0.75 * x + 0.4 * x + 20 = 403\]
=> \[1.15 * x = 403 - 20\]
=> \[1.15 * x = 383\]
=> \[x = 383/1.15\]
=> \[x = 333\]
Number of seniors having job in 2010 = 0.4 * (333 + 50) = 0.4 * 383 = 153.2 = 153(approx)
<span>The answer for the question above is C) 9.88-10.12</span>
Based on the annual income, the payment period, and the amount deducted for the 403(b), the amount deposited into Sandy's 403(b) is $220.
<h3>How much is deposited into Sandy's 403(b)?</h3>
First find the biweekly income:
= 51,350 / (52 weeks / 2 )
= 51,350 / 21 weeks
= $2,445.24
5% is deducted from her wages and the employer matches 4% of the salary. The amount deposited is:
= (5% + 4%) x 2,445.24
= $220
Find out more on 403(b) at brainly.com/question/2908111.
Equation of the line:
y = -4x + 1
