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tatiyna
3 years ago
7

What is y^4-36 in simplest factored form?

Mathematics
1 answer:
Bond [772]3 years ago
6 0
y^4-36=(y^2)^2-6^2=(y^2-6)(y^2+6)=[y^2-(\sqrt6)^2](y^2+6)\\\\=(y-\sqrt6)(y+\sqrt6)(y^2+6)\\\\\\\\\\a^2-b^2=(a-b)(a+b)
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The number 14,688 rounded to the nearest ten is 14,680
melamori03 [73]
This is false the number 14,688 rounded to the nearest ten is not 14,680. You went down instead of going up.
7 0
3 years ago
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She has $10.00 to spend. Apples cost $0.26 each and oranges cost $0.38 each. If Samantha can only buy apples, how many apples ca
Pachacha [2.7K]

Answer:

she can buy 38 apples

Step-by-step explanation:

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What values of b satisfy 3(26 + 3)² = 36?
MakcuM [25]

The numeric value of the b is 0.23 which satisfy the given equation.

According to the statement

We have to find that the value of the b.

So, For this purpose, we know that the

The numeric value refers to the worth of each digit depending on where it lies in the number.

From the given information:

The equation is a

3(2b + 3)² = 36

then to find the value of b rearrange the terms then

(2b + 3)² = 12

(2b + 3) =  \sqrt{12}

(2b) =   \sqrt{12}  -3

then

b  = \sqrt{12}  -3/ 2

b = 3.46 - 3/2

b = 0.46/2

b = 0.23.

So, The numeric value of the b is 0.23 which satisfy the given equation.

Learn more about numeric value here

brainly.com/question/24703884

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7 0
1 year ago
Orthogonally diagonalize the​ matrix, giving an orthogonal matrix P and a diagonal matrix D. To save​ time, the eigenvalues are
alexgriva [62]

Answer:

P=\left(\begin{array}{ccc}-\frac{2}{3}&-\frac{2}{3}&\frac{1}{3}\\\frac{1}{\sqrt{5}}&0&\frac{2}{\sqrt{5}}\\-\frac{4}{3\sqrt{5}}&\frac{\sqrt{5}}{3}&\frac{2}{3\sqrt{5}}\end{array}\right)

Step-by-step explanation:

It is a result that a matrix A is orthogonally diagonalizable if and only if A is a symmetric matrix.  According with the data you provided the matrix should be

A=\left(\begin{array}{ccc}-9&-4&2\\ -4&-9&2\\2&2&-6\\\end{array}\right)

We know that its eigenvalues are \lambda_{1}=-14, \lambda_{2}=-5, where \lambda_{2}=-5 has multiplicity two.

So if we calculate the corresponding eigenspaces for each eigenvalue we have

E_{\lambda_{1}=-14}=\langle(-2,-2,1)\rangle,E_{\lambda_{2}=-5}=\langle(1,0,2),(-1,1,0)\rangle..

With this in mind we can form the matrices P, D that diagonalizes the matrix A so.

P=\left(\begin{array}{ccc}-2&-2&1\\1&0&2\\-1&1&0\\\end{array}\right)

and

D=\left(\begin{array}{ccc}-14&0&0\\0&-5&0\\0&0&-5\\\end{array}\right)

Observe that the rows of P are the eigenvectors corresponding to the eigen values.

Now you only need to normalize each row of P dividing by its norm, as a row vector.

The matrix you have to obtain is the matrix shown below

3 0
3 years ago
For the function y=-2sin(pi/12(x-2) what is the maximum value
pogonyaev

Answer:

Step-by-step explanation:

The max value of the sine function is 1.  

If we multiply it by 2, we get 2 sin x, whose max. value is 2.

If we multiply the sine function by -2, the max value of this functin is still 2.

3 0
3 years ago
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