Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be parallel, they need to have the same slope.
y - 3x = 2 Add 3x on both sides to change the equation to slope-intercept form
y - 3x + 3x = 2 + 3x
y = 3x + 2 The slope is 3, so the parallel line's slope is also 3.
Now that you know the slope, substitute/plug it into the equation
y = mx + b
y = 3x + b To find "b", plug in the point (6, 1) into the equation, then isolate/get the variable "b" by itself
1 = 3(6) + b
1 = 18 + b Subtract 18 on both sides to get "b" by itself
1 - 18 = 18 - 18 + b
-17 = b
y = 3x - 17 Your answer is the 1st option
Answer:
m<ADC = 42°
Step-by-step explanation:
Based on the inscribed angle theorem, the inscribed angle, m<ADC is ½ the measure of minor arc AC.
If minor arc is given as 84°, therefore:
m<ADC = ½(84)
m<ADC = 42°
Answer:

General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]:
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Product Rule]: ![\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bf%28x%29g%28x%29%5D%3Df%27%28x%29g%28x%29%20%2B%20g%27%28x%29f%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- [Function] Derivative Rule [Product Rule]:
![\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B9x%5E%7B10%7D%5D%20%5Ctan%5E%7B-1%7D%28x%29%20%2B%209x%5E%7B10%7D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctan%5E%7B-1%7D%28x%29%5D)
- Rewrite [Derivative Property - Multiplied Constant]:
![\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%209%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5E%7B10%7D%5D%20%5Ctan%5E%7B-1%7D%28x%29%20%2B%209x%5E%7B10%7D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctan%5E%7B-1%7D%28x%29%5D)
- Basic Power Rule:
![\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%2090x%5E9%20%5Ctan%5E%7B-1%7D%28x%29%20%2B%209x%5E%7B10%7D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctan%5E%7B-1%7D%28x%29%5D)
- Arctrig Derivative:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
Answer:
755 gram lighter
Step-by-step explanation:
Convert 1.1kg into gram by multiplying it with 1000
1.1 x 1000= 1100 and we take this amount and subtract it with 345g
1100-345= 755g
V = 1/3Bh
B = 1/2(b1 + b2)t
V = 1/3[1/2(b1 + b2)t] * h
h = 24
b1 = 13
b2 = 29
t = ?
V = 2856
Substitute:
2856 = 1/3[1/2(13 + 29)t](24)
2856 = 1/6(42)(24)t
2856 = 7(24)t
2856 = 168t
t = 2856/168 = 17 in height of the trapeziod