Ask question

Ask question

All categories

3 years ago

12

I need to know the answer to p=4x-140

1 answer:

dalvyx [7]3 years ago

7 0

This is not look like something that could be answered, check around the paper for a graphing box.
This looks like a formula for a line on a graph: y=Mx+b. I can help you if this is the case, 1. Put a point at -140 on the Y axis (up and down) 2. Move up 1 and over 4and put a dot there( you could multiply the 1 and 4 to cover a larger area) because it goes all the way to -140.

You might be interested in

13) (3 + 7v2)(3 – 7v2)

Dovator [93]

Answer:

the answer to this problem is

9 - 21v^2 + 21v^2 - 49v^4

9 - 49v^4

Step-by-step explanation:

8 0

3 years ago

288 miles on 12 gallons of fuel; 240 miles on 10 gallons of fuel

Arisa [49]

288 divided by 12 = 24
240 divided by 10 = 24

6 0

3 years ago

Ilia_Sergeevich [38]

Answer:

2

Step-by-step explanation:

Given

See attachment for chart

Required

Number of off days

To do this, we simply calculate the expected value of the chart.

This is calculated as:

$E(x) = \sum x * f$

Where

x = days

f = chances

So, we have:

$E(x) = 0* 0.3 + 1 *0.2 + 2 * 0.25 + 3 * 0.2 + 4 * 0.02 + 5 * 0.01 + 6 * 0.01 + 7 * 0.01$

$E(x) = 1.56$

$E(x) \approx 2$

3 0

2 years ago

How do I solve the equation in an interval from 0 to 2π ? 9 cos 2t = 6

Ivahew [28]

$9\cos(2t)=6\implies\cos(2t)=\dfrac23$

Using the fact that cos is 2π-periodic, we have

$\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi$

That is, $\cos(\theta+2n\pi)=\cos\theta$ for any $\theta$ and integer $n$ .

$\implies t=\dfrac12\cos^{-1}\left(\dfrac23\right)+n\pi$

We get 2 solutions in the interval [0, 2π] for $n=0$ and $n=1$ ,

$t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi$

4 0

2 years ago

Evaluate the expression and enter your answer in the box below |98|

olganol [36]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to evaluate $\pmb{|98|}$ .

$\triangle~\fbox{\bf{KEY:}}$

The notation |x| denotes absolute value.

The absolute value of a number is its distance from zero.

Absolute value is always positive; distances can't be negative, right?

So we need to find the absolute value of 98, which is:

$\star~\star\mathrm{98}~\star~\star$

$\ddot\bigstar$ Remember this...

$\fbox{The\;absolute\;value\;is\;a\;number's\;distance\;from\;zero}$

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

3 0

2 years ago