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3 years ago

A sample is a subset of all possible data values for a given subject under consideration.

Mathematics

1 answer:

Tom [10]3 years ago

3 0

Answer: True

Step-by-step explanation:

A subset is a term used in the sets topic In mathematics to describe a Part of A larger values being considered.

Sample In experimental procedures is known as Part of what is to be used to determine the reaction of a larger mass of specimen.

Taking these two definitions by side, it is quite evident that both of them represent taking part of a larger picture to form a smaller picture which does not totally deviate from the larger picture being considered.

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Use Definition 7.1.1,

Maksim231197 [3]

Answer:

1q1231564rr54drdfgy6

7 0

2 years ago

An art studio charges a start-up fee to cover art supplies, plus an additional fee per class. The graph shows the total cost for

Studentka2010 [4]

Answer/Step-by-step explanation:

✔️The rate of change can be calculated using the coordinates of any two points on the graph. Let's use (2, 60) and (3, 75):

$rate of change = \frac{y_2 - y_1}{x_2 - x_1} = \frac{75 - 60}{1} = \frac{15}{1} = 15$

Rate of change (m) = 15

✅In the context of this situation, the rate of change can be interpreted to be the additional fee per class. Thus, an additional fee per class cost $15.

✔️Initial value is the same as the y-intercept.

To find the y-intercept (b), substitute m = 15, x = 2, and y = 60 into y = mx + b.

Thus:

60 = 15(2) + b

60 = 30 + b

60 - 30 = b

30 = b

b = 30

The initial value/y-intercept = $30

✅In this context, $30 is the start-up fee to cover art supplies.

5 0

2 years ago

In Exercises 6 and 7, use the given measure to find the missing value in each data set. 6. The mean of the ages of 5 brothers is

strojnjashka [21]

Solution

Problem 6

For this case we can do this:

12, 16,__, 14, 8, 7

We can solve for x like this:

$\frac{12+16+x+14+8+7}{6}=13$ $x=13\cdot6-(12+16+14+8+7)=21$

Problem 7

7 0

1 year ago

Suppose that y varies inversely as x, and x=9 when y=15. Find the value for k and write the function. Group of answer choices La

Radda [10]

Answer:

see explanation

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition that x = 9 when y = 15

15 = $\frac{k}{9}$ ( multiply both sides by 9 )

k = 135

y = $\frac{135}{x}$ ← equation of variation

8 0

3 years ago

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

3 years ago