Please help me now ! Thank you
1 answer:
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now 2x^2+18 = 10 2x^2+18-18 = 10-18 <<--- step 1 2x^2 = -8 (2x^2)/2 = -8/2 <<--- step 2 x^2 = -4 At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. For example 2^2 = 2*2 = 4 8^2 = 8*8 = 64 (-10)^2 = (-10)*(-10) = 100 (-14)^2 = (-14)*(-14) = 196 No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative. So x^2 = -4 has no real solutions. Taking the square root of both sides leads to x^2 = -4 sqrt(x^2) = sqrt(-4) |x| = sqrt(4)*sqrt(-1) |x| = 2*i x = 2i or x = -2i which are complex non-real values
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I hope this helps you! Have a good day!
Answer:
A. Dilation of scale factor 2
B. Reflection over the y-axis
C. Reflection over the line y=x
D. Translation 1 unit left and 1 unit up
Answer:
8 and 8√3
Step-by-step explanation:
Sin90 = b/8
1 x 8 =b
b=8
Tan 30 = 8/a
1/√3 = 8/a
a=8√3