All categories

4 years ago

A reaction will occur when CaCl2 is combined with _______. A) F2 B) N2 C) Br2 D) I2

Chemistry

1 answer:

mamaluj [8]4 years ago

7 0

Answer:

A reaction will occur when CaCl2 is combined with F2.

Explanation:

Let us know the terms at first.

Ca- Calcium

Cl2- Chloride, therefore CaCl2 is Ca+ Cl2 and that is calcium chloride.

Now, F2 is fluorine which is a yellow compressed gas.

When CaCl2 combines with F2, it gives out products like CaF2 or calcium fluoride, which is a white crystalline solid in powder form, and Cl or chlorine, which appears as a greenish-yellow compressed liquid gas with a pungent smell.

Here is the equation,

CaCl2+ F2= CaF2+ Cl.

You might be interested in

What precaution should be used when dealing with sulfuric acid in this experiment and why?

ryzh [129]

Sulfuric acid is capable of hurting the skin, eyes, paper, metals, and even stone in some cases.

4 0

3 years ago

Which can occur during a physical change? (Select all that apply.)

koban [17]

Answer:

the shape of a piece of matter can change

7 0

3 years ago

If 21.42g of KMnO4 is actually produced what is the percent yield

mrs_skeptik [129]

Answer:

Percentage yield = 6.776%

Explanation:

Data Given:

Actual yield of KMnO₄ = 21.42g

Percentage Yield = ?

Formula Used to find Percent yield

Percentage yield = Actual yield/ theoretical yield x 100 (1)

For this Pupose First step is

We have to know the theoretical yield KMnO₄

Potasium permagnate form from MnO₄ and KOH in the presence of Oxygen by heating, in 1st step in second 2K₂MnO₄ react with HCl and give KMnO₄ .

The Reactions of formation of KMnO₄

1st Step

2MnO₄ + 4KOH + O₂ ------------> 2K₂MnO₄ + 2H₂O

2nd Step

2K₂MnO₄ + 4HCl ------------->2 KMnO₄ + H₂O + 4KCl

So form the above equation we come to know it produced 2 Mole of KMnO₄

Now we will calculate the mass of KMnO₄ by mass formulae

mass of KMnO₄ = Number of mole of KMnO₄ x Molar Mass of KMnO₄

Molar Mass of KMnO₄ = 158.034g /mol

Put value in Mass Formula

mass of KMnO₄ = 2 mol x 158.034g/mol

mass of KMnO₄ = 316.1 g

So the theoratical yield per standard reaction = 316.1 g

Now put all values in equation 1

Percentage yield = Actual yield/ theoretical yield x 100

Percentage yield = 21.42g / 316.1 g x 100

Percentage yield = 0.0678 x 100

Percentage yield = 6.776%

4 0

3 years ago

Which of the following would have the highest lattice energy?

Ilia_Sergeevich [38]

Answer:

MgN3

Explanation:

In MgN3 the charge on the ionic species is greater than NaCl. So,ionic interactions in MgN3 will be stronger

4 0

3 years ago

(a) starting with solid sucrose, c12h22o11, describe how you would prepare 250 ml of a 0.250 m sucrose solution. (b) de- scribe

Anna007 [38]

a. We first calculate the moles of sucrose needed

moles sucrose = 0.250 M * 0.25 L

moles sucrose = 0.0625 mol

The molar mass of sucrose 342.3 g/mol, so the mass of sucrose needed is:

mass sucrose = 0.0625 mol * 342.3 g/mol

mass sucrose = 21.4 grams

So simply dissolved about 21.4 grams of sucrose in 250 mL solution.

b. We use the formula:

M1 V1 = M2 V2

1.50 M * V1 = 0.100 M * 0.350 L

V1 = 0.0233 L = 23.3 mL

So simply take 23.3 mL of solution from 1.50 M then dilute it with water until 350 mL to make 0.100 M.

5 0

4 years ago