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ArbitrLikvidat [17]
3 years ago
14

A Gouy balance is used to determine the magnetic susceptibility of a substance. A strong electromagnet is placed next to the sam

ple, which is on a balance. If the sample is paramagnetic, the mass reading of the balance will increase when the field is switched on. Based on their electron configurations, predict whether these elements are paramagnetic or diamagnetic.
Paramagnetic ...Diamagnetic
He ,Mg ,s ,Li
Chemistry
1 answer:
prohojiy [21]3 years ago
3 0

Answer:

Paramagnetic - S , Li

Diamagnetic - He , Mg

Explanation:

Paramagnetic are those which has unpaired electrons and diamagnetic are those in which all electrons are paired.

Given

<u>He, the atomic number - 2</u>

The electronic configuration is -  

1s^2

The electrons in 1s orbital = 2 (Paired)

Thus, the element is diamagnetic as the electrons are paired.

<u>Mg, the atomic number - 12</u>

The electronic configuration is -  

1s^22s^22p^63s^2

The electrons in 3s orbital = 2 (Paired)

Thus, the element is diamagnetic as the electrons are paired.

<u>S, the atomic number - 16</u>

The electronic configuration is -  

1s^22s^22p^63s^23p^4

The electrons in 3p orbital = 4 (Unpaired)

Thus, the element is paramagnetic as the electrons are unpaired.

<u>Li, the atomic number - 3</u>

The electronic configuration is -  

1s^22s^1

The electrons in 2s orbital = 1 (Unpaired)

Thus, the element is paramagnetic as the electrons are unpaired.

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Answer:

Malachite green has highest percentage of copper.

Explanation:

Azurite: 2CuCO_3.Cu(OH)_2

Molar mass of Azurite = M = 344.67 g/mol

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Percentage of copper in Azurite :

Cu\%=\frac{3\times 63.55 g/mol}{344.67 g/mol}\times 100=55.31\%

The percentage of copper in an azurite is 55.31%.

Malachite: CuCO_3.Cu(OH)_2

Molar mass of Malachite = M = 221.12 g/mol

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Percentage of copper in Malachite:

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The percentage of copper in an malachite is 57.48%.

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172 °C = __________ K<br> (Round off to the nearest whole number)
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Solid lead acetate is slowly added to 75.0 mL of a 0.0492 M sodium sulfate solution. What is the concentration of lead ion requi
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The concentration of lead ion required to just initiate precipitation is -2.37\times10^-^5 M

Explanation:

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Solubility product of PbI_2 ,Q=[Pb^2^+]_i_n_i_t_i_a_l [I^-]^2_i_n_i_t_i_a_l =9.8\times10^-^9

Concentration of I^-=[KI]=0.0492M

When the ionic product exceeds the solubility product , precipitation of salt takes place .

                                   Q_s_p\geq K_s_p

        [Pb^2^+]_i_n_i_t_i_a_l [I^-]^2_i_n_i_t_i_a_l \geq 9.8\times10^-^9

      [Pb^2^+]_i_n_i_t_i_a_l  [0.0492]^2 \geq 9.8\times10^-^9

                       [Pb^2^+]_i_n_i_t_i_a_l \geq \frac{9.8\times10^-^9}{[0.0492]^2}

                        [Pb^2^+]_i_n_i_t_i_a_l \geq \frac{9.8\times10^-^9}{2.42\times10^-^3}

                        [Pb^2^+]_i_n_i_t_i_a_l \geq 2.37\times10^-^5 M

Thus , PbI_2 will start precipitating when [Pb^2^+]_i_n_i_t_i_a_l   \geq 2.37\times10^-^5 M.    

3 0
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