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Alexxandr [17]
4 years ago
12

Wavelength of 3.7x10^14

Chemistry
1 answer:
UkoKoshka [18]4 years ago
4 0
8.1*10tothe14hz thanks for askin
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What is the mass of 0.0490 mole of potassium sulfate?
Angelina_Jolie [31]

Answer:

8.54g

Explanation:

we know that: n=m/Mm

where:

  • n represents moles
  • m represent mass
  • and Mm represents molar mass

rearrange for m: m= n x Mm

m= 0.0490mol x 174.259g/mol

m= 8.54g

7 0
3 years ago
What is the arrangement of electron pairs of pbr3? predict the molecular shape of a pbr3 molecule?
mina [271]
Check the attached file for the solution. The shape is in the next file.

3 0
4 years ago
Convert 0.00763 nL to L
Reptile [31]

Answer:

7.63\cdot10^{-12} L

Explanation:

Conversion problems could be solved using dimensional analysis for convenient use and understanding. Dimensional analysis is a technique of multiplying the measure we have by a fraction corresponding to some two equal measures in different units.

In order to apply dimensional analysis here, we firstly need to know that a prefix 'n' stands for 'nano', and nano means 10^{-9}. In this case, we have nanoliters. Using the prefix, we can find a relationship between nanoliter and liter:

1 nL = 10^{-9} nL

We may now apply dimensional analysis. Since we wish to convert into liters, we'll be multiplying the number we have in nL by a fraction that contains this relationship with liters in the numerator and nanoliters in the denominator, so that nL terms cancel out and we would obtain the final answer in liters:

0.00763 nL\cdot \frac{10^{-9} L}{1 nL}=7.63\cdot10^{-12} L

6 0
3 years ago
Silver nitrate solution reacts with calcium chloride solution according to the equation: 2 AgNO3 + CaCl2 → Ca(NO3)2 + 2 AgCl All
HACTEHA [7]

Answer:

14.33 g

Explanation:

Solve this problem based on the stoichiometry of the reaction.

To do that we need the molecular weight of the masses involved and then calculate the number of moles, find the limiting reagent and  finally calculate the mass of AgCl.

                      2 AgNO₃   + CaCl₂    ⇒   Ca(NO₃)₂   + 2 AgCl

mass, g                  6.97        6.39                                     ?

MW ,g/mol         169.87      110.98                                  143.32

mol =m/MW           0.10         0.06                                    0.10

From the table above AgNO₃ is the limiting reagent and we will produce 0.10 mol AgCl which is a mass :

0.10 mol x 143.32 g/mol = 14.33 g

5 0
4 years ago
Enter the net ionic equation for this reaction. Express your answer as a net ionic equation. Identify all of the phases in your
Lisa [10]

Answer:

2H+(aq) + 2OH-(aq) → 2H2O(l)

Explanation:

Step 1: The balanced equation

2HCl(aq)+Ca(OH)2(aq) → 2H2O(l)+CaCl2(aq)

This equation is balanced, we do not have the change any coefficients.

Step 2: The netionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will.

2H+(aq) + 2Cl-(aq) + Ca^2+(aq) + 2OH-(aq) → 2H2O(l) + Ca^2+(aq) + 2Cl-(aq)

After canceling those spectator ions in both side, look like this:

2H+(aq) + 2OH-(aq) → 2H2O(l)

6 0
3 years ago
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