$\sin^{2} \theta+\cos^{2} \theta=1 \\ \\ \sin^{2} \theta+\left(\frac{\sqrt{3}}{3} \right)^{2}=1 \\ \\ \sin^{2} \theta+\frac{1}{3}=1 \\ \\ \sin^{2} \theta=\frac{2}{3} \\ \\ \theta=-\frac{\sqrt{2}}{\sqrt{3}}=\boxed{-\frac{\sqrt{6}}{3}}$

5 0

1 year ago

Choose all of the points that would be on a graph for y=7x

pav-90 [236]

Hey there! :D

Plug in the points to see if they work.

y=7x

(2,14) -> (x,y)

14=7*2

14=14

That works.

(0,0)

0=7*0

0=0

That works

(1,7)

7=7*1

7=7

That works.

The points that work are (2,14), (0,0), and (1,7)

I hope this helps!
~kaikers

3 0

3 years ago

Which of these points lies on the line described by the equation below y-4=-2(x-6)?​

Which of these points lies on the line described by the equation below y-4=-2(x-6)?