All categories

2 years ago

(-3/10) (-5/12) you have to multiply

Mathematics

2 answers:

Ilia_Sergeevich [38]2 years ago

7 0

Answer:

1/8

Step-by-step explanation:

Multiply the two numerators to get the product numerator

-3 X -5 = 15

Multiply the two denominators to get the product denominator

10 X 12 = 120

(-3/10) (-5/12)

=15/120

Reduce the fraction by dividing top and bottom by 15.

15/15 = 1

120/15=8

The answer is 1/8.

Rom4ik [11]2 years ago

7 0

Answer:

1/8

<h3>Step by Step Instructions</h3>

$\frac{ - 3}{10} \times \frac{ - 5}{12}$
$\frac{ - 3}{10} \times \frac{ - 5}{12} = \frac{15}{120}$
$\frac{15}{120} = \frac{1}{8}$
$\frac{1}{8}$

<h3>Notes:</h3>

Because both fractions are negative, your answer is a positive.
To multiply fractions, multiply the numerators and denominators

You might be interested in

563 - 89 show your work

pickupchik [31]

The answer is 474 very simple.

5 0

2 years ago

I need help with this question please.

garri49 [273]

Answer:

Yes, the ratio stays 2:3

Step-by-step explanation:

3 0

2 years ago

2, 6, 10, 14, ...

8090 [49]

The sequence can be represented by $2 + 4x$ , where $x$ is a whole number( $x \geq 0$ and $x$ is an integer). By this, we should be able to plug in some whole number x and be able to get these values if they are in the sequence. To test this, let's set these numbers equal to $2 + 4x$ and confirm that there is a whole number x which equals the values selected.

$2 + 4x = 90 \Rightarrow 4x = 88 \Rightarrow x = 22 \, \checkmark$

$2 + 4x = 150 \Rightarrow 4x = 148 \Rightarrow x = 37 \, \checkmark$

$2 + 4x = 160 \Rightarrow 4x = 158 \Rightarrow x = 39.5$

When trying 160 with our equation, we find that x doesn't equal a whole number, thus our answer is C, or 160. To confirm our answer, we can test 170 and 210 and confirm that they both give us a value for x which is a whole number.

$2 + 4x = 170 \Rightarrow 4x = 168 \Rightarrow x = 42 \, \checkmark$

$2 + 4x = 210 \Rightarrow 4x = 208 \Rightarrow x = 52 \, \checkmark$

6 0

2 years ago

I will mark branliest please

Greeley [361]

Answer:

1.) Right

2.)Acute

3.) obtuse

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

8 0

3 years ago