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3 years ago

Domain and range helllllllllllllllllllllllllllppppp

Mathematics

1 answer:

charle [14.2K]3 years ago

7 0

Na I don't wanna do this one

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The amount of revenue for a business can be modeled by the function

GarryVolchara [31]

God loves all of you, remember that oK. Thts really all u need in life <3 7 if u know answer in comments - 8400(3)2t= H is

5 0

2 years ago

220 students were asked if they liked chocolate or vanilla ice cream. 140 said they liked chocolate and 120 said they liked vani

Flura [38]

Answer: D. 40

Step-by-step explanation:

Given: Number of students liked vanilla or chocolate ice cream = $n(V\cup C)=220$

Number of students liked chocolate = $n(C)=140$

Number of students liked vanilla= $n(V)=120$

Now, Number of students liked vanilla and chocolate ice cream is given by :-

$n(V\cap C)=n(C)+n(V)-n(V\cup C)\\\\\Rightarrown(V\cap C)=140+120-220\\\\\Rightarrown(V\cap C)=260-220\\\\\Rightarrown(V\cap C)=40$

Number of students liked vanilla and chocolate ice cream= 40

6 0

4 years ago

A flower garden is shaped like a circle. Its diameter is 40yd. A ring-shaped path goes around the garden. The width of the path

stellarik [79]

Answer:

Number of sand bags needed = 124

Step-by-step explanation:

Diameter of garden = 40 yd

Width of path = 6 yd

Diameter of garden with path = 40 + 2 x 6 = 52 yd

We need to find area of path.

Area of path = Area of garden with path - area of garden

$\texttt{Area of path = }\frac{\pi \times 52^2}{4}-\frac{\pi \times 40^2}{4}\\\\\texttt{Area of path = }867.08yd^2$

Area covered by one sand bag = 7 yd²

$\texttt{Number of sand bags required = }\frac{\texttt{Area of path}}{\texttt{Area covered by one sand bag}}\\\\\texttt{Number of sand bags required = }\frac{867.08}{7}=123.86\approx 124$

Number of sand bags needed = 124

8 0

4 years ago

IS IT (A , B ) CAN SOMEONE HELP PLEASE !!!!!!!!!!!!!!!!!

andriy [413]

Answer: 1% is your answer

It's (1/100) * 100 or 1% is the percentage strength of a 1:100 solution.

Step-by-step explanation:

l NOTE:

l To change ratio strength to percent strength, it is

sometimes convenient to "convert" the last two zeros in

a ratio strength to a percent sign (%),

l change the remaining ratio to a common fraction, and

then to a decimal fraction in expressing percent.

l Examples:

l 1:100 =1/1% = 1%

l 1:200 = ½% = 0.5%

l 3:500 = 3/5% = 0.6%

l 1:2500 = l/25% = 0.04%

l 1:10,000 = 1/100% = 0.01%

8 0

2 years ago

y = An isosceles triangle A B C with horizontal base A B and vertex C is below the base. Side A C and C B are labeled with singl

yarga [219]

34 is your answer

hope this helps

3 0

3 years ago