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cluponka [151]
3 years ago
6

Domain and range helllllllllllllllllllllllllllppppp

Mathematics
1 answer:
charle [14.2K]3 years ago
7 0
Na I don't wanna do this one

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Area of a trapezium is 31.5cm. If the parallel sides are of lengths 7.3cm and 5.3cm. Calculate the perpendicular distance betwee
Anna11 [10]

Answer:

5cm

Step-by-step explanation:

Given area of trapezium = 31.5 sq. cm

Length of parallel sides = 7.3cm and 5.3cm

Formula to calculate area of trapezium is

1/2*(sum of parallel sides)*perpendicular distance between parallel sides

sum of parallel sides =  (7.3 + 5.3) = 12.6cm

substituting value of area given and sum of parallel sides we have

31.5 = 1/2* 12.6 * perpendicular distance between parallel sides

(31.5 * 2)/12.6 = perpendicular distance between parallel sides

perpendicular distance between parallel sides = 63/12.6 = 5

Therefore perpendicular distance between parallel sides for given trapezium is 5cm.

5 0
3 years ago
314,207 in standard form expanded form and word form
Gennadij [26K]
Three hundred fourteen thousand two hundread seven

Hope it helps!!
8 0
3 years ago
Read 2 more answers
Given one zero of the polynomial function, find the other zeros.
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

You need to use synthetic division to do all of these.  The thing to remember with these is that when you start off with a certain degree polyomial, what you get on the bottom line after the division is called the depressed polynomial (NOT because it has to math all summer!) because it is a degree lesser than what you started.

a.  3I   1   3   -34   48

I'm going to do this one in its entirety so you get the idea of how to do it, then you'll be able to do it on your own.

First step is to bring down the first number after the bold line, 1.

3I   1    3    -34    48

   _____________

      1

then multiply it by the 3 and put it up under the 3.  Add those together:

3I    1    3    -34    48

           3

----------------------------

      1     6

Now I'm going to multiply the 6 by the 3 after the bold line and add:

3I    1     3     -34     48                                                                                                    

             3      18

_________________

      1      6     -16

Same process, I'm going to multiply the -16 by the 3 after the bold line and add:

3I      1      3      -34      48

                3       18     -48

___________________

        1       6      -16       0

That last zero tells me that x-3 is a factor of that polynomial, AND that the depressed polynomial is one degree lesser and those numbers there under that line represent the leading coefficients of the depressed polynomial:

x^2+6x-16=0

Factoring that depressed polynomial will give you the remaining zeros.  Because this was originally a third degree polynomial, there are 3 zeros as solutions.  Factoring that depressed polynomial gives you the remaining zeros of x = -8 and x = 2

I am assuming that since you are doing synthetic division that you have already learned the quadratic formula.  You could use that or just "regular" factoring would do the trick on all of them.

Do the remaining problems like that one; all of them come out to a 0 as the last "number" under the line.

You got this!        

4 0
3 years ago
You travel 5 miles downstream in a kayak at a speed of r miles per hour. You turn around and travel 6 miles upstream at a speed
Vlad1618 [11]
Kyle, d = rt, right? This means that t = d/r. If we call the rate of the current c, then her rate upstream is hindered by the current and is 3 - c. Downstream is 3 + c. The total time is 6 hours... 5/(3 - c) + 5/(3 + c) = 6 Once we put everything over the same denominator, we don't need it anymore. 5(3 + c) + 5(3 - c) = 6(3 - c)(3 + c) 15 + 5c + 15 - 5c = 54 - 6c2
30 = 54 - 6c26c2 = 24c2 = 4c = 2 2 mph 
3 0
3 years ago
Pls help 20 points TYYY
Mumz [18]
Answer: A

Explanation:
It is exponential because the y value is multiplied by 3 each time.
6 0
3 years ago
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