<span>A. the area of the circular base multiplied by the height of the cylinder B. the circumference of the circular base multiplied by the height of the cylinder C. the sum of the areas of the two circular bases multiplied by the height of the cylinder D.</span>

4 0

3 years ago

(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x

Aliun [14]

As

$\tan x=\dfrac{\sin x}{\cos x}$
$\cot x=\dfrac{\cos x}{\sin x}$

we have

$\sin x(\tan x\cos x-\cot x\cos x)=\sin x\left(\sin x-\dfrac{\cos^2x}{\sin x}\right)=\sin^2x-\cos^2x$

Recalling that $\cos2x=\cos^2x-\sin^2x$ , we end up with

$-\cos2x=1-2\cos2x$
$1=\cos2x$
$\implies2x=2n\pi$

(where $n$ is any integer)

$\implies x=n\pi$

5 0

3 years ago

Yes or no awnser pls

kifflom [539]

Answer:

No the question iant a function

5 0

2 years ago