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brilliants [131]
3 years ago
14

Therasa had $150.She spent more than $50 at the grocery store. Write an inequality to show the mount she has left

Mathematics
2 answers:
Leviafan [203]3 years ago
5 0
150-50 =100
i think that is the answer
now can some one help me plz plz 

Sphinxa [80]3 years ago
5 0

I may have wrote it wrong but 
If the value is not part of the solution, the symbols to use <, >
if the value is part of the solution the symbols to use \leq ,  \geq

x + $50 \leq 150
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Mark bikes 4/10 of a mile in 1/5 of an hour. Find marks average speed in miles per hour.
Triss [41]

He bikes 4/10 of a mile in 1/5 of an hour

That is 4/10 miles in 1/5 hours

Average speed = Distance/ time = 4/10 ÷ 1/5 = 4/10 × 5/1 = 2 miles/hour

6 0
3 years ago
A manufacturer of lawnmowers wanted to know the most important product attributes to consumers. The company's research team deve
stepladder [879]

Answer: Ordinal measurement scale

Step-by-step explanation:

In ordinal measurement scale the order of values or variables are very important. Just as in the case above, the rating from 1-3 is according to the order of it's importance.

Thanks

7 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
PLEASE I REALLY NEED HELP
vovangra [49]

Answer:

who think

Step-by-step explanation:

5 0
2 years ago
HELP When does expanding and simplifying a(b + c) result in a positive value for ac?
Reil [10]

Answer:

When c and a are positive or both are negative

Step-by-step explanation:

negative times negative equals positive so if a was negative and c was negative -a*-c= ac

Of course positive times positive equals negative so if a and c were positive we could do

a*c= ac

Hope I could help !

7 0
2 years ago
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