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scoundrel [369]
3 years ago
5

What parts of the cell are used to connect an electrochemical cell to a circuit?

Chemistry
1 answer:
Sophie [7]3 years ago
5 0
I think it's the Terminals

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Consider molecular, complete ionic, and net ionic equations.
8090 [49]

Explanation:

(a) The molecular equations shows the equation in which all the species of the reactants and the products are in molecules and the net charge is zero.

The complete ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and are represented as ions.

The net ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and do not show the spectator ions which are same in the reactants and the products.

(b) If there is no spectator ions in the reaction, then the complete and the net ionic equations would be identical.

3 0
3 years ago
Is filtration physical or chemical
Lesechka [4]

Answer:

physical

Explanation:

Mixtures can be separated through physical changes, including techniques such as chromatography, distillation, evaporation, and filtration.

8 0
4 years ago
Which state of matter takes the shape but NOT the volume of its container?
Mumz [18]

Answer:

solids and liquids

Explanation:

3 0
4 years ago
Read 2 more answers
When Fe2O3(s) reacts with H2(g) to form Fe(s) and H2O(g), 98.8 kJ of energy are absorbed for each mole of Fe2O3(s) that reacts.
vfiekz [6]

Answer:

Explanation:

Fe₂O₃(s) + 3H₂(g)  =  2Fe (s) + 3H₂O - 98.8 kJ .

one mole of ferric oxide reacts with 3 mole of hydrogen to give 2 mole of iron and 3 mole of water .   98.8 kJ of heat is absorbed .

7 0
3 years ago
Rank the following chemical species from largest ionic radius to smallest ionic radius
7nadin3 [17]

Answer:

Biggest Radii     V²⁺ > V³⁺ > V⁴⁺ > V⁵⁺     Smallest Radii

General Formulas and Concepts:

  • Periodic Trends: Atomic/Ionic Radii
  • Coulomb's Law

Explanation:

The Periodic Trend for Atomic Radii is down and to the left. Therefore, the element with the largest radius would be in the bottom left corner of the Periodic Table.

Anions will always have a bigger radii than the parent radii. When we add e⁻ to the element, we are increasing the e⁻/e⁻ repulsions. This will cause e⁻ to repel themselves more and thus create more space, increasing the radii size.

Cations will always have smaller radii than the parent radii. When we remove e⁻ from the element, we are decreasing e⁻/e⁻ repulsions. Since there are less e⁻, there is no need for more space and thus decreases the radii size.

Since Cations are smaller than the parent radii, the more e⁻ we remove, the smaller it will become.

Therefore, the least removed e⁻ Vanadium would be the largest and the most removed e⁻ Vanadium would be the smallest.

4 0
3 years ago
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