The Nuclear Model-1909. Ernest Rutherford's great contribution to atomic theory was to show what happens to an element during radioactive decay. This enabled him to construct the first nuclear model of the atom, a cornerstone of present-day physics The Nuclear Model-1909.
The answer is True I hope this helps
The answer for the following question is answered below.
- <em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>
Explanation:
Given:
Initial pressure of the gas = 1.34 atm
Initial temperature of the gas = 273 K
final temperature of the gas = 312 K
To solve:
Final temperature of the gas
We know;
From the ideal gas equation
P × V = n × R × T
So;
from the above equation we can say that
<em>P ∝ T</em>
= constant
=
Where;
= initial pressure of a gas
= final pressure of a gas
= initial temperature of a gas
= final temperature of a gas
=
= 1.76 atm
<em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>
Answer:
19.3 g/cm³
Explanation:
From the question given above, the following data were obtained:
Mass of nugget of gold = 965 g
Volume of nugget of gold = 50 cm³
Density =?
The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, it is expressed as:
Density = mass / volume
With the above formula, we can obtain the density of the nugget of gold as illustrated below:
Mass of nugget of gold = 965 g
Volume of nugget of gold = 50 cm³
Density of nugget of gold =?
Density = mass / volume
Density of nugget of gold = 965 / 50
Density of nugget of gold = 19.3 g/cm³
Thus, the density of the nugget of gold is 19.3 g/cm³.
The conversion is easily done by knowing first the conversion from one unit to other. The useful conversions from the given are: 1 cm³ = 1 mL, 1 L = 1000 mL. Performing the dimensional analysis,
(17.3 cm³) x (1 mL / 1 cm³) x (1 L / 1000 mL ) = 0.0173 L
Therefore, 17.3 cm³ is equal to 0.0173 L.