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solniwko [45]
3 years ago
10

1. What is the empirical formula for a compound containing 63.8% N and 36.2% O?

Chemistry
1 answer:
Fittoniya [83]3 years ago
3 0
M\ N_2=28g/mol\\
63,8\%--28g\\
100\%--x\\
x=43,89g

43,89g≈44g
44g == 2x 14g (N) + 1x 16x(O)
M N₂O = 44g

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