All categories

3 years ago

Write the balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI.

1 answer:

4 0

If it is just a simple double-replacement reaction, then the balanced equation is simply:

Pb(ClO3)2(aq) + 2 NaI(aq) = PbI2 + 2 Na(ClO3)

However, if this is a precipitation reaction, we must identify which compound will precipitate (is insoluble), either NaClO3 or PbI2

NaClO3 is soluble, PbI2 is not. Only the lead cations and iodine anions will participate in the reaction.

thus, the balanced equation is: Pb^(2+) + 2I^(-) ==> PbI2

You might be interested in

Please if anyone know this question, tell me its answer. I will be very thankful to you

Verizon [17]

Ch-c§c will get the answer

5 0

3 years ago

Students are completing a table about a particular subatomic particle that helps make up an atom. The students have filled in on

Semmy [17]

Answer:
 Its location is in the nucleus, because the particle is a proton or a neutron.

5 0

3 years ago

Read 2 more answers

explain how the number of valence electrons in atoms relate to their bonding with other atoms to form molecules ?????

Westkost [7]

valence electrons are the number of electrons in the outer shell. there can only be 8 electrons in the outer shell. The number of valence electrons can be used to determine how many bonds are needed.

For example: H2O

O (oxygen) has 6 valence electrons
H (hydrogen) has 1 valence electron

O needs 2 more electrons to be stable
H needs 1 more electron to be stable

O forms one bond with two H atoms to form H2O.

5 0

3 years ago

What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a

Vadim26 [7]

Answer:

$\boxed {\boxed {\sf 333 \ grams}}$

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

$Q= mc \Delta T$

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

ΔT= final temperature - initial temperature

The sample was heated from 58.8 degrees Celsius to 88.9 degrees Celsius.

ΔT= 88.9 °C - 58.8 °C = 30.1 °C

Now we know three variables:

Q= 4500.0 J
c= 0.4494 J/g°C
ΔT = 30.1 °C

Substitute these values into the formula.

$4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)$

Multiply on the right side of the equation. The units of degrees Celsius cancel.

$4500.0 \ J = m (13.52694 J/g)$

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

$\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}$

The units of Joules cancel.

$\frac {4500.0 \ J }{13.52694 J/g}= m$

$332.6694729 \ g =m$

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

$333 \ g \approx m$

The mass of the sample of metal is approximately 333 grams.

8 0

2 years ago

A can of soda is 335ml what is 2 cans of soda in ml

Snezhnost [94]

I can =335ml
2cans=?

2cans×335ml÷1
= 670ml

5 0

3 years ago