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jeka57 [31]
3 years ago
11

Write the balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI.

Chemistry
1 answer:
Kaylis [27]3 years ago
4 0
If it is just a simple double-replacement reaction, then the balanced equation is simply:

Pb(ClO3)2(aq) + 2 NaI(aq) = PbI2 + 2 Na(ClO3)

However, if this is a precipitation reaction, we must identify which compound will precipitate (is insoluble), either NaClO3 or PbI2

NaClO3 is soluble, PbI2 is not. Only the lead cations and iodine anions will participate in the reaction.

thus, the balanced equation is: Pb^(2+)  +  2I^(-)  ==>  PbI2
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3 years ago
How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?
faltersainse [42]

Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

  • Volume of the solution (V): 500 mL
  • Molar concentration of the solution (M): 0.8 M = 0.8 mol/L

Step 2: Convert "V" to L

We will use the conversion factor 1 L = 1000 mL.

500 mL × 1 L/1000 mL = 0.500 L

Step 3: Calculate the moles of KBr (solute)

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2 years ago
Question 6
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