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tia_tia [17]
3 years ago
12

Which of the following changes will increase the frequency of the lowest frequency standing sound wave on a stretching string?Ch

oose all that apply.A. Replacing the string with a thicker stringB. Plucking the string harderC. Doubling the length of the string
Physics
1 answer:
Margaret [11]3 years ago
7 0

Answer:

A, C

Explanation:

Since the frequency is inversely proportional to the length of a string, then I want to increase the frequency of the lowest

A. Replacing the string with a thicker string.

Thicker strings have more density. The more density the string has, the lower the sound.

Mathematically, we can see the proportionality (direct and inverse) by looking at those formulas for Frequency and Speed, when combined:

For:

f=\frac{v}{\lambda}

f=\frac{v}{\lambda}*\sqrt{\frac{T}{D} }

See above, how density (D) and (\lambda) wave length are inversely proportional.

C. Doubling the length of the string.

Because the length of the string is inversely proportional to the frequency.

The longer the string, the lower the frequency.

So, if we double string, we'll hear lower sounds in any string instrument

--

In short,  for A, and C  We can justify both since length and density are inversely proportional to the Frequency, we need longer or thicker string.

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Calculate the magnitude of the normal force on a 25.2 kg block in the following circumstances. (Enter your answers in N.) HINT (
irga5000 [103]

Answer:

when the body is resting N = 246.96 N

when the body is resting on a tilted surface N = 212.12 N.

when the body is in a elevator N = 317.036 N

Explanation:

when the block is resting on a stationary surface the normal force is balanced by the weight of the body.

weight of the body = mg = 25.2×9.8 = 246.96 N

therefore normal force = 246.98 N.

when the block is resting on a tilted surface the normal force will be balanced by the \cos \theta component of the weight where Ф is the angle of inclination.

therefore N = mg\cos \Phi

                N= 212.12 N.

when the block is resting on a elevator that is accelerated upward the normal force will be the sum of weight and force due to acceleration ma

therefore N = 246.98 + 25.2×2.78

N = 317.036 N

5 0
4 years ago
A quarter-wave monopole radio antenna (also called a Marconi antenna) consists of a long conductor of one quarter the length of
sasho [114]

Answer:

a) Height of the antenna (in m) for a radio station broadcasting at 604 kHz = 124.17 m

b)Height of the antenna (in m) for radio stations broadcasting at 1,710 kHz =43.86 m

Explanation:

(a) Radiowave wavelength= λ = c/f

As we know, Radiowave speed in the air = c = 3 x 10^8 m/s

f = frequency = 604 kHz = 604 x 10^3 Hz

Hence, wavelength = (3x10^8/604x10^3) m

λ = 496.69 m

So the height of the antenna BROADCASTING AT 604 kHz =  λ /4 = (496.69/4) m

= 124.17 m

(b) As we know , f = 1710 kHz = 1710 x 10^3 Hz  (1kHZ = 1000 Hz)

Hence, wavelength =  λ = (3 x 10^8/1710 x 10^3) m

 λ= 175.44 m

So, height of the antenna =  λ /4 = (175.44/4) m

= 43.86 m  

5 0
4 years ago
If the 78.0 kg astronaut were in a spacecraft 6R from the center of the earth, what would the astronaut's weight be on earth? 76
den301095 [7]

(a) 764.4 N

The weight of the astronaut on Earth is given by:

F=mg

where

m is the astronaut's mass

g is the acceleration due to gravity

Here we have

m = 78.0 kg

g = 9.8 m/s^2 at the Earth's surface

So the weight of the astronaut is

F=(78.0)(9.8)=764.4 N

(b) 21.1 N

The spacecraft is located at a distance of

r=6R

from the center of Earth.

The acceleration due to gravity at a generic distance r from the Earth's center is

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass.

We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:

GM=9.8R^2 (1)

the acceleration due to gravity at r=6R instead will be

g'=\frac{GM}{(6R)^2}

And substituting (1) into this formula,

g'=\frac{9.8R^2}{36R^2}=0.27 m/s^2

So the weight of the astronaut at the spacecratf location is

F'=mg'=(78.0 kg)(0.27 m/s^2)=21.1 N

6 0
4 years ago
Which material is the LEAST dense?
givi [52]
Brick has least dense
8 0
4 years ago
Read 2 more answers
Please help i don’t get this
antoniya [11.8K]

Answer:

i think it is with friction because when we move we go against friction so like when were walking friction is trying to decrease our speed

Explanation:

3 0
3 years ago
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