Volumetric flasks are most accurate
Answer:
68.8 N 13.8°N of W
Explanation:
F₁ is 50 N 30°N of W. The terminal angle is 150°.
F₂ is 25 N 20°S of W. The terminal angle is -160°.
Graphically, you can add the vectors using head-to-tail method. Move F₂ so that the tail of the vector is at the head of F₁. The resultant vector will be from the tail of F₁ to the head of F₂.
Algebraically, find the x and y components of each vector.
F₁ₓ = 50 N cos(150°) = -43.3 N
F₁ᵧ = 50 N sin(150°) = 25 N
F₂ₓ = 25 N cos(-160°) = -23.5 N
F₂ᵧ = 25 N sin(-160°) = -8.6 N
The x and y components of the resultant vector are the sums:
Fₓ = -43.3 N + -23.5 N = -66.8 N
Fᵧ = 25 N + -8.6 N = 16.4 N
The magnitude of the resultant force is:
F = √(Fₓ² + Fᵧ²)
F = √((-66.8 N)² + (16.4 N)²)
F = 68.8 N
The direction of the resultant force is:
θ = tan⁻¹(Fᵧ / Fₓ)
θ = tan⁻¹(16.4 N / -66.8 N)
θ = 166.2°
θ = 13.8°N of W
Answer:
A) electric field strength between the plates;E = 2 x 10^(6) N/C
B) exit velocity;v = 8.39 x 10^(7) m/s
Explanation:
We are given;
Potential difference; V = 20 kV = 20000 V
Distance between the 2 parallel plates; d = 1cm = 0.01 m
A) The electric field strength will be gotten from;
E = V/d
E = 20000/0.01
E = 2000000
E = 2 x 10^(6) N/C
B) For exit speed, we'll use the formula for Kinetic energy; KE = (1/2)mv²
KE is also expressed as; V•q_e
Thus,
(1/2)mv² = V•q_e
Where;
V is potential difference = 20000 V
Q_e is charge of electron which has a constant value of; (1.6 x 10^(-19))C
m is mass of electron with a constant value of (9.1 x 10^(-31)) kg
v is the velocity
Thus, making v the subject, we have;
v = √((2V•q_e)/m)
v = √((2 x 20000•(1.6 x 10^(-19)))/(9.1 x 10^(-31)))
v = 83862786 m/s or
v = 8.39 x 10^(7) m/s
To produce a single sugar molecule a plant must use a molecule of water (H2O) and carbon dioxide (CO2) and sunlight. To get 4 molecules, you simple use 4 molecules of water and 4 molecules of carbon dioxide.
No problem! :D
